Old good absolute values : Quant Question Archive [LOCKED]
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# Old good absolute values

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SVP
Joined: 03 Feb 2003
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10 Jun 2004, 03:50
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Old good absolute values...
solve the equation

|x-1|=|x^2 - 1|
Manager
Joined: 07 May 2004
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Re: Old good absolute values [#permalink]

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10 Jun 2004, 03:54
stolyar wrote:
Old good absolute values...
solve the equation

|x-1|=|x^2 - 1|

|x-1|=|x-1|*|x+1| =>

1) x = 1

2) |x+1| = 1 => x = 0, -2.

0, -1 and 2 = answers.
Manager
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10 Jun 2004, 04:04
stolyar wrote:
wrong

Why? Both 0, -2 and 1 satisfy this equation (simply put 0, 1, and -2) into it and see. Are there any other answers?
SVP
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10 Jun 2004, 04:07
U wrote: 0, -1 and 2 = answers.
Incorrect

the correct set is [-2, 1, and 0]
Manager
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10 Jun 2004, 04:11
stolyar wrote:
U wrote: 0, -1 and 2 = answers.
Incorrect

the correct set is [-2, 1, and 0]

Yes, I changed signs before -2 and 1

But I think, that this misprint is really clear when compared to the solution...
Manager
Joined: 07 May 2004
Posts: 183
Location: Ukraine, Russia(part-time)
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Kudos [?]: 15 [0], given: 0

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10 Jun 2004, 04:11
ob wrote:
x = 0, x = 1.

No, -2 is a solution too.
Senior Manager
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10 Jun 2004, 04:13
Oops, missed one more value!
10 Jun 2004, 04:13
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