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On a 20 mile course, Pat bicycled at an average rate of 30

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On a 20 mile course, Pat bicycled at an average rate of 30 [#permalink]

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New post 30 Dec 2012, 05:11
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On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?

A. 75
B. 105
C. 117
D. 150
E. 162
[Reveal] Spoiler: OA

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Last edited by Bunuel on 30 Dec 2012, 05:37, edited 2 times in total.
Renamed the topic and edited the question.
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Re: On a 20 mile course, Pat bicycled at an average rate of 30 [#permalink]

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New post 30 Dec 2012, 05:44
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sananoor wrote:
On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?

A. 75
B. 105
C. 117
D. 150
E. 162


At an average rate of 30 miles per hour in 12 minute (1/5 hours) Pat covers (distance) = (time) * (rate) = 1/5*30 = 6 miles, thus she should cover the remaining distance of 20 - 6 = 14 miles at an average rate of 8 miles per hour.

To cover 14 miles at an average rate of 8 miles per hour Pat needs (time) = (distance)/(rate) = 14/8 = 1.75 hours = 105 minutes.

Therefore Pat needs total of 12 + 105 = 117 minutes to cover the entire course.

Answer: C.
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Re: On a 20 mile course, Pat bicycled at an average rate of 30 [#permalink]

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New post 30 Dec 2012, 06:11
i was doing absolutely right but was taking time in minutes rather than in hours...now a days i am so much worried about up coming gmat test that i am making a lot of mistakes...thanks a million
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Re: On a 20 mile course, Pat bicycled at an average rate of 30 [#permalink]

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New post 31 May 2015, 19:22
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Re: On a 20 mile course, Pat bicycled at an average rate of 30   [#permalink] 31 May 2015, 19:22
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