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# On a certain road 10 percent of hte motorists exceed the

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Director
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On a certain road 10 percent of hte motorists exceed the [#permalink]

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16 Jan 2005, 11:33
On a certain road 10 percent of hte motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of hte motorists who exceed the posted speed limit do not receive speeding tickets. what percent of the motorists on the road exceed the posted speed limit?

A)10 1/2%
B)12 1/2%
C)15%
D)22%
E)30%
Director
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16 Jan 2005, 15:24
B) 12.5%

Let there be 100 motorists on the road. 10 get speeding tickets.
Let number of motorists who exceed speed limit = x
Given 80% of x= 10
So x= 12.5
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16 Jan 2005, 16:36
the question gave me an impression that.. 20% is not related with the 10%
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16 Jan 2005, 16:44
vprabhala wrote:
the question gave me an impression that.. 20% is not related with the 10%

The question says that 20% of those who exceeded the posted speed limit did not get a ticket, which means 80% of those who did got a ticket.

It says that 10% the motorists exceed the posted speed limit and receive speeding tickets.

So you can equate the two.
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16 Jan 2005, 16:47
gayathri wrote:
vprabhala wrote:
the question gave me an impression that.. 20% is not related with the 10%

The question says that 20% of those who exceeded the posted speed limit did not get a ticket, which means 80% of those who did got a ticket.

It says that 10% the motorists exceed the posted speed limit and receive speeding tickets.

So you can equate the two.

yuppie.. should be more careful....
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09 Sep 2011, 23:53
Let the number of motorists, m be 100.

10% of m = 10 (those who speed and get a ticket)

Let the number of motorists who speed be s

Therefore, if 20%(s) = no. of motorists who speed but do not get a ticket, no. of motorists who speed and get a ticket = 100%(s) - 20%(s) = 80%(s) = 10

Therefore, if 80%(s) = 10; s = 12.5 people = 12.5% (when m = 100)
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Re: Motorists   [#permalink] 09 Sep 2011, 23:53
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