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On a certain scale of intensity, each increment of 10 in

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VP
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New post 21 Mar 2005, 23:17
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On a certain scale of intensity, each increment of 10 in magnitude represents a tenfold increase in intensity. On this scale, an intensity corresponding to a magnitude of 165 is how many times an intensity corresponding to a magnitude of 125?

(A) 40
(B) 100
(C) 400
(D) 1,000
(E) 10,000

guys F1.
Senior Manager
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New post 22 Mar 2005, 01:18
(E)

Intensity for magnitude 125 -> x
Intensity for magnitude 125 + 10 -> 10x
Intensity for magnitude 125 + 20 -> 100x
Intensity for magnitude 125 + 30 -> 1000x
Intensity for magnitude 125 + 40 = 165 -> 10000x
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New post 22 Mar 2005, 07:13
165-125=40

so each increment of 10 and that happens 4 times.. which will be equal to 10*10*10*10.

E.
  [#permalink] 22 Mar 2005, 07:13
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On a certain scale of intensity, each increment of 10 in

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