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On a certain sight-seeing tour, the ratio of the number of

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On a certain sight-seeing tour, the ratio of the number of [#permalink] New post 09 Aug 2008, 00:09
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On a certain sight-seeing tour, the ratio of the number of women to the number of children was 5 to 2. What was the number of men on the sight-seeing tour?

(1) On the sight-seeing tour, the ratio of the number of children to the number of men was 5 to 11.
(2) The number of women on the sight-seeing tour was less than 30.
[Reveal] Spoiler: OA

Last edited by Bunuel on 29 Oct 2012, 14:06, edited 1 time in total.
OA added.
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Re: DS - Sight Seeing Tour [#permalink] New post 09 Aug 2008, 00:31
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clubzzang wrote:
Ppl, pls help me solve this q.

On a certain sight-seeing tour, the ratio of the number of women to the number of children was 5 to 2. What was the number of men on the sight-seeing tour?

(1) On the sight-seeing tour, the ratio of the number of chilren to the number of men was 5 to 11.
(2) The number of women on the sight-seeing tour was less than 30.

Thanks!


C.

w:c = 5:2

1) c:m = 5:11

w:c:m = 25:10:22

But this does not give us exact number of men

2) this itself does not tell anything about number of men.

Toegther, since number of women is less than 30 and since the number of ppl will always be an integer and also that
25:10:22 can not be reduced further => there will be 25 women => there will be 22 men. thus suff
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Re: DS - Sight Seeing Tour [#permalink] New post 07 Sep 2010, 11:52
could someone explain this differently please
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Re: DS - Sight Seeing Tour [#permalink] New post 07 Sep 2010, 11:59
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aiming4mba wrote:
could someone explain this differently please


On a certain sight-seeing tour, the ratio of the number of women to the number of children was 5 to 2. What was the number of men on the sight-seeing tour?

Given: \frac{w}{c}=\frac{5}{2} --> w=5x and c=2x for some integer x. Q: m=?

(1) on the sight-seeing tour, the ratio of the number of children to the number of men was 5 to 11 --> \frac{c}{m}=\frac{5}{11} --> c=5y and m=11y, for some integer y. Not sufficient to calculate m.

(2) the number of women on the sight-seeing tour was less than 30 --> w<30. Not sufficient to calculate m.

(1)+(2) w=5x<30 --> x<6. c=2x and as c=5y, c is a multiple of 5 --> x=5 --> c=10=5y --> y=2 --> m=11y=22. Sufficient.

Answer: C.

OR: \frac{\frac{w}{c}}{m}=\frac{\frac{25}{10}}{22} --> \frac{w}{m}=\frac{25}{22} and as w<30, then w=25 because for other values of w<30, m (and c) are not integers --> m=22.

Hope it's clear.
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tour [#permalink] New post 06 Apr 2011, 10:02
W/C = 5/2

(1) M = 11C/5. this means C has to be a multiple of 5 (C = 5 M/11) insuff.

(2) W < 30 , here w/c could be 5/2, 10/4, 20/8, 25/10 insuff.

Combining both, only 25/10 works
M= 11*10/5= 22
Ans. C
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Re: Sightseeing tour- DS [#permalink] New post 07 Apr 2011, 03:07
Yurik79 wrote:
My answer is C
from 1 statement we can find out the whole ratio W to Child and Men alone insuf because we need not ratio but number
from statement 2 alone we dn't get anything

1 and 2 together do the job!My approuch to DS may be wrong but why to solve further if you already know that from 1 and 2 we can figure out the answer!IMHO


Further calculations may be needed because the lowest number of women needed to satisfy the ratio may be > 30, in which case the answer would've been E. So just changing the ratios a bit can change the answer.
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Re: Sightseeing tour- DS [#permalink] New post 29 May 2011, 06:42
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Another specific way of answering:
Given w/c= 5/2, c = 2/5(w)
(1) c/m = 5/11, m = 11/5(c) insufficient
(2) w < 30, no information about men, insufficient.

Considering C:
m = 11/5c
= 11/5 * 2/5(w)
= 22/25(w) and w < 30 here only 25 is a multiple of 25. so w = 5
= 22
Ans. C.
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Re: Sightseeing tour- DS [#permalink] New post 20 Nov 2011, 22:12
Baten80 wrote:
Another specific way of answering:
Given w/c= 5/2, c = 2/5(w)
(1) c/m = 5/11, m = 11/5(c) insufficient
(2) w < 30, no information about men, insufficient.

Considering C:
m = 11/5c
= 11/5 * 2/5(w)
= 22/25(w) and w < 30 here only 25 is a multiple of 25. so w = 5
= 22
Ans. C.


Hi

Sorry I got a bit lost in the logic. Also, i completely do understand the significance of the sentence below in this Q

2. The number of women on the sightseeing tour was less than 30.

Would appreciate your help.

I get how m = 22/25(w)

but then you have mentioned only 25 is a multiple of 25. so w = 5. If we replace 5 with w in this eq -> m = 22/25(w)
then m would be 22/5 and not 22? Did you mean to say w = 25 (and mistyped 5)?

Please help.
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Re: On a certain sightseeing tour, the ratio of the number of [#permalink] New post 15 Jan 2012, 15:24
This is how I solved it :

Given - W/C = 5/2

From statement 1 we get
C/M = 5/11

with this we can get W/M = 25/22

Since we dont the number it wont help so insiffucient.

Statement 2 - we get Women less than 30. wont help So insufficnet.

Combining.

We know that W/M = 25/22 and women # is less that 30 it will be possible only if men are 22 in number based on the ratio we derived from statement 1.
so answer C
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Re: On a certain sight-seeing tour, the ratio of the number of [#permalink] New post 22 May 2013, 02:40
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Re: On a certain sight-seeing tour, the ratio of the number of [#permalink] New post 11 Jul 2014, 06:57
Brunel,
why can the number not of women not be 0.
25x:10x:22x
with x=0 both statements would still told true.
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Re: On a certain sight-seeing tour, the ratio of the number of [#permalink] New post 11 Jul 2014, 10:33
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LTN99 wrote:
Brunel,
why can the number not of women not be 0.
25x:10x:22x
with x=0 both statements would still told true.


That's not true. If x=0, then w = m = c = 0. But in this case none of the ratios given is true because 0/0 is undefined and not 5:2 or 5:11.
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On a certain sight-seeing tour, the ratio of the number of [#permalink] New post 24 Jul 2014, 10:09
Is that correct?

from the question, we know W/C = 5/2 so C=2W/5

1) <=> C/M = 5/2 <=> M=11C/5
we plug C

M=22W/25 Insufficient

2) clearly insufficient

1+2) from 2) W must be a multiple of 25 inferior to 30. so W=25
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Re: On a certain sight-seeing tour, the ratio of the number of [#permalink] New post 24 Jul 2014, 10:16
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oss198 wrote:
Is that correct?

from the question, we know W/C = 5/2 so C=2W/5

1) <=> C/M = 5/2 <=> M=11C/5
we plug C

M=22W/25 Insufficient

2) clearly insufficient

1+2) from 2) W must be a multiple of 25 inferior to 30. so W=25


Yes, that's correct.
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Re: On a certain sight-seeing tour, the ratio of the number of [#permalink] New post 19 Oct 2014, 02:29
One small doubt regarding this. When it says that the number of women is less than 30, wouldn't 0 be a valid scenario?
In that case number of men would be 0 too .. so it could either be 22 men or 0 men.

Hence option E.

I know 0 sounds a bit illogical but in mathematical terms, it is possible I guess. Please advise. :roll:
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Re: On a certain sight-seeing tour, the ratio of the number of [#permalink] New post 19 Oct 2014, 03:10
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rakhauri wrote:
One small doubt regarding this. When it says that the number of women is less than 30, wouldn't 0 be a valid scenario?
In that case number of men would be 0 too .. so it could either be 22 men or 0 men.

Hence option E.

I know 0 sounds a bit illogical but in mathematical terms, it is possible I guess. Please advise. :roll:


Please read the whole thread: on-a-certain-sight-seeing-tour-the-ratio-of-the-number-of-68645.html#p1382219
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Re: On a certain sight-seeing tour, the ratio of the number of   [#permalink] 19 Oct 2014, 03:10
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