arjtryarjtry wrote:

On a certain tour, half of the men are married, and the wives of 9/10 of them are also on the tour.

If there are 3 more women on the tour than men, what is the least possible number of people who could be on the tour?

(A) 19

(B) 22

(C) 23

(D) 43

(E) 52

I used answer choices to solve

split (Married Men, Unmarried men, women-3 , 3 women )

A) 19 --> 4 4 8 3 [ 8*9/10 -- not integer ]

B) 22 --> 4.25 4.25 9.5 3

C) 23 --> 5 5 10 3 [ 5*9/10 not an integer ]

C) 43 --> 10 10 20 3 [10*9/10 Integer]. _________________

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