On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?
A. 33 1/3%
E. 66 2/3%
I also got C but with a slightly different approach.
If 60% of the passengers with round trip tickets did not take their cars that means 40% of the passengers with round trip tickets took their car which equates to 20% of the total of ship passengers.
This translates to 30% of the total of ship passengers who had round trip tickets but did not take their car. (60/40 x 20%) = 30%
Thus to find the total nnumber of round trip ticket holders, you just add the two. 20% + 30% = 50%