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# On a certain transatlantic crossing, 20 percent of a ship s

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On a certain transatlantic crossing, 20 percent of a ship s [#permalink]

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07 Sep 2008, 10:48
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?

A. 33 1/3%
B. 40%
C. 50%
D. 60%
E. 66 2/3%
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07 Sep 2008, 11:39
Nihit wrote:
On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?

A. 33 1/3%
B. 40%
C. 50%
D. 60%
E. 66 2/3%

x= total no.of ship's passengers
y= total no.of passengers with round trip

0.2x=No.of passengers have round-trip tickets and also took their cars abroad the ship
0.6y=passengers with round-trip tickets did not take their cars abroad the ship

0.2x=0.4y
y=0.5x

50%

C
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07 Sep 2008, 23:08
Another C. I have seen a similar problem in disguise on this post.
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10 Sep 2008, 03:56
C it is, though the language is pretty tricky.
Re: round trip ticket   [#permalink] 10 Sep 2008, 03:56
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