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# On a certain transatlantic crossing, 20 percent of a ships

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VP
Joined: 26 Apr 2004
Posts: 1225
Location: Taiwan
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On a certain transatlantic crossing, 20 percent of a ships [#permalink]  31 Jan 2005, 08:58
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On a certain transatlantic crossing, 20 percent of a shipâ€™s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the shipâ€™s passengers held round-trip tickets?

A. 33 1/3%
B. 40%
C. 50%
D. 60%
E. 66 2/3%
VP
Joined: 18 Nov 2004
Posts: 1442
Followers: 2

Kudos [?]: 20 [0], given: 0

[#permalink]  31 Jan 2005, 09:27
"C"...50 %

If 100 ppl onboard and X have round trip tickets, then

20 + 0.6X = X

X = 50
Current Student
Joined: 28 Dec 2004
Posts: 3391
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 13

Kudos [?]: 181 [0], given: 2

[#permalink]  31 Jan 2005, 09:42
banarjee is right! 50%

with these problems, always pick a number. 100 is good since we have % invlolved!

20% of 100=20 Roundtrip with cars.

X is the total number of Roundtrip tkt holders

60% of X dont have cars!

20+0.6x=x

x=50....since total number of passengers is 100, therefor 50% are roundtrip tkt holders...
Manager
Joined: 28 Jan 2005
Posts: 101
Followers: 1

Kudos [?]: 1 [0], given: 0

[#permalink]  01 Feb 2005, 05:22
right. U can always draw a table to visualize easier.
[#permalink] 01 Feb 2005, 05:22
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# On a certain transatlantic crossing, 20 percent of a ships

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