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On a certain transatlantic crossing, 20 percent of a ships

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VP
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On a certain transatlantic crossing, 20 percent of a ships [#permalink] New post 31 Jan 2005, 08:58
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On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?

A. 33 1/3%
B. 40%
C. 50%
D. 60%
E. 66 2/3%
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 [#permalink] New post 31 Jan 2005, 09:27
"C"...50 %

If 100 ppl onboard and X have round trip tickets, then

20 + 0.6X = X

X = 50
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 [#permalink] New post 31 Jan 2005, 09:42
banarjee is right! 50%

with these problems, always pick a number. 100 is good since we have % invlolved!

20% of 100=20 Roundtrip with cars.

X is the total number of Roundtrip tkt holders

60% of X dont have cars!

20+0.6x=x

x=50....since total number of passengers is 100, therefor 50% are roundtrip tkt holders...
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 [#permalink] New post 01 Feb 2005, 05:22
right. U can always draw a table to visualize easier.
  [#permalink] 01 Feb 2005, 05:22
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On a certain transatlantic crossing, 20 percent of a ships

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