On a certain trip, a cyclist averaged 20 miles per hour for

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On a certain trip, a cyclist averaged 20 miles per hour for [#permalink]

31 Mar 2012, 02:24

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Question Stats:

76% (02:58) correct

23% (01:12) wrong

based on 21 sessions

On a certain trip, a cyclist averaged 20 miles per hour for the 10 miles and 16 miles per hour for the remaining 20 miles. If the cyclist returned immediately via the same route and took a total of 4 hours for the round trip, what was the average speed, in miles, for the return trip?

A. 24
B. 18
C. 17 1/7
D. 15
E. 13 1/3

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Re: On a certain trip, a cyclist averaged 20 miles per hour for [#permalink]

31 Mar 2012, 05:13

eybrj2 wrote:

One way trip is 20 miles plus 10 miles = 30 miles;

For the first part of the trip the cyclist needed time=distance/rate=10/20+20/16=7/4 hours;

Hence for the return trip the cyclist needed 4-7/4=9/4 hours;

The average speed for the return trip is miles/time=30/time=30/(9/4)=13.(3).

Answer: E.
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Re: On a certain trip, a cyclist averaged 20 miles per hour for [#permalink] 31 Mar 2012, 05:13

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On a certain trip, a cyclist averaged 20 miles per hour for

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On a certain trip, a cyclist averaged 20 miles per hour for

On a certain trip, a cyclist averaged 20 miles per hour for

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