Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 30 Aug 2015, 17:12

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

On a graph the four corners of a certain quadrilateral

Author Message
TAGS:
Intern
Joined: 18 Dec 2012
Posts: 5
Followers: 0

Kudos [?]: 9 [0], given: 11

On a graph the four corners of a certain quadrilateral [#permalink]  04 Jan 2013, 02:06
1
This post was
BOOKMARKED
00:00

Difficulty:

65% (hard)

Question Stats:

64% (02:26) correct 36% (01:51) wrong based on 70 sessions
On a graph the four corners of a certain quadrilateral are (a,5), (b,5), (a,0) and (b,0). If a + c = 12, a < b and both a and b are positive values then what is the area of the quadrilateral?

(1) b + c = 6
(2) The quadrilateral is a rectangle.
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 29151
Followers: 4729

Kudos [?]: 49823 [2] , given: 7498

Re: On a graph the four corners of a certain quadrilateral [#permalink]  04 Jan 2013, 03:41
2
KUDOS
Expert's post
trex16864 wrote:
On a graph the four corners of a certain quadrilateral are (a,5), (b,5), (a,0) and (b,0). If a + c = 12, a < b and both a and b are positive values then what is the area of the quadrilateral?

(1) b + c = 6
(2) The quadrilateral is a rectangle.

There is a problem with this question. We are given that a + c = 12 and (1) says that b + c = 6, thus a = b + 6, which implies that a > b. But the stem says that a < b. I guess it should be a > b instead of a < b.

In this case the question would be:
On a graph the four corners of a certain quadrilateral are (a,5), (b,5), (a,0) and (b,0). If a + c = 12, a > b and both a and b are positive values then what is the area of the quadrilateral?

Look at the diagram below:
Attachment:

Quadrilateral.PNG [ 9.43 KiB | Viewed 2332 times ]
As we can see given quadrilateral is a rectangle and its area = 5*(a-b).

(1) b + c = 6. Since a + c = 12 and b + c = 6, then a - b = 6. Area = 5*6=30. Sufficient.

(2) The quadrilateral is a rectangle. We already know that. Not sufficient.

Hope it's clear.
_________________
Intern
Joined: 18 Dec 2012
Posts: 5
Followers: 0

Kudos [?]: 9 [0], given: 11

Re: On a graph the four corners of a certain quadrilateral [#permalink]  04 Jan 2013, 02:54
My solution:

Given the information in the question we can already conclude, that the quadriliteral is a rectangle with a width of 5. We need to figure out the length of the rectangle in order to find the area.

(1) with
I) $$a + c = 12$$
II) $$b + c = 6$$

we can I) - II) => $$(a-b) = 6$$

Length = Distance [(a;5) (b;5)] = Distance [(a;0) (b;0)] =
= SQR [ $$(a-b)^2 + (5-5)^2$$ ]
= SQR [ $$6^2 + 0^2$$ ]

= 6

=> $$Area = 6 * 5 = 30$$ sufficient

(2) We already know that we have a rectangle. The statement gives us no further information about the length. Not sufficent

Hence A

Last edited by trex16864 on 04 Jan 2013, 04:04, edited 2 times in total.
Intern
Joined: 08 Sep 2012
Posts: 7
Followers: 0

Kudos [?]: 3 [0], given: 28

Re: On a graph the four corners of a certain quadrilateral [#permalink]  01 Jun 2013, 00:16
Bunuel wrote:
trex16864 wrote:
On a graph the four corners of a certain quadrilateral are (a,5), (b,5), (a,0) and (b,0). If a + c = 12, a < b and both a and b are positive values then what is the area of the quadrilateral?

(1) b + c = 6
(2) The quadrilateral is a rectangle.

There is a problem with this question. We are given that a + c = 12 and (1) says that b + c = 6, thus a = b + 6, which implies that a > b. But the stem says that a < b. I guess it should be a > b instead of a < b.

In this case the question would be:
On a graph the four corners of a certain quadrilateral are (a,5), (b,5), (a,0) and (b,0). If a + c = 12, a > b and both a and b are positive values then what is the area of the quadrilateral?

Look at the diagram below:
Attachment:
As we can see given quadrilateral is a rectangle and its area = 5*(a-b).

(1) b + c = 6. Since a + c = 12 and b + c = 6, then a - b = 6. Area = 5*6=30. Sufficient.

(2) The quadrilateral is a rectangle. We already know that. Not sufficient.

Hope it's clear.

Hi,

Sorry to re-open the thread. But Can you please explain how does the question stem tells us that it is a rectangle?

Thank you
Math Expert
Joined: 02 Sep 2009
Posts: 29151
Followers: 4729

Kudos [?]: 49823 [0], given: 7498

Re: On a graph the four corners of a certain quadrilateral [#permalink]  01 Jun 2013, 03:17
Expert's post
Genfi wrote:
Bunuel wrote:
trex16864 wrote:
On a graph the four corners of a certain quadrilateral are (a,5), (b,5), (a,0) and (b,0). If a + c = 12, a < b and both a and b are positive values then what is the area of the quadrilateral?

(1) b + c = 6
(2) The quadrilateral is a rectangle.

There is a problem with this question. We are given that a + c = 12 and (1) says that b + c = 6, thus a = b + 6, which implies that a > b. But the stem says that a < b. I guess it should be a > b instead of a < b.

In this case the question would be:
On a graph the four corners of a certain quadrilateral are (a,5), (b,5), (a,0) and (b,0). If a + c = 12, a > b and both a and b are positive values then what is the area of the quadrilateral?

Look at the diagram below:
Attachment:
As we can see given quadrilateral is a rectangle and its area = 5*(a-b).

(1) b + c = 6. Since a + c = 12 and b + c = 6, then a - b = 6. Area = 5*6=30. Sufficient.

(2) The quadrilateral is a rectangle. We already know that. Not sufficient.

Hope it's clear.

Hi,

Sorry to re-open the thread. But Can you please explain how does the question stem tells us that it is a rectangle?

Thank you

Mark (a,5), (b,5), (a,0) and (b,0) on the plane and you'll see that you'll get a rectangle for any values of a and b (a>b).
_________________
Intern
Joined: 22 Feb 2013
Posts: 9
Followers: 0

Kudos [?]: 1 [0], given: 4

Re: On a graph the four corners of a certain quadrilateral [#permalink]  01 Jun 2013, 15:27
The b > a threw me off...
Re: On a graph the four corners of a certain quadrilateral   [#permalink] 01 Jun 2013, 15:27
Similar topics Replies Last post
Similar
Topics:
Is quadrilateral a square? 3 03 Apr 2012, 06:27
6 Is the quadrilateral a square? 10 11 Feb 2012, 13:08
1 ABCD is a quadrilateral. A rhombus is a quadrilateral whose 14 29 Dec 2010, 07:08
13 Is quadrilateral ABCD a rhombus? 23 14 Oct 2009, 20:09
1 Is quadrilateral Q a square? 10 28 Nov 2007, 14:19
Display posts from previous: Sort by