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# On July 1 of last year, the total number of employees at

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Manager
Joined: 05 Jul 2006
Posts: 198
Followers: 1

Kudos [?]: 20 [0], given: 0

On July 1 of last year, the total number of employees at [#permalink]  02 Aug 2006, 15:53
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
On July 1 of last year, the total number of employees at Company E was decreased by 10%. Without any change in salaries of the remaining employees, the average (arithmetic mean) employee salary was 10% more than after the decrease in number of employees than before the decrase. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 last year?

A.90%
B.99%
C.100%
D.101%
E.110%
VP
Joined: 02 Jun 2006
Posts: 1267
Followers: 2

Kudos [?]: 42 [0], given: 0

B.99%

Savg = Sum/E

After decrease

1.1Savg = Sum'/0.9E

=> Sum' = 11/10 x Savg x 9/10

=> Sum' = 0.99Sum

Manager
Joined: 25 Jul 2006
Posts: 100
Followers: 1

Kudos [?]: 4 [0], given: 0

B....

# of people before = 100
salary before = 10
Total salary = 1000

# of people after = 90
salary after = 11
Total salary = 990

% = 990/1000 = 99%
SVP
Joined: 30 Mar 2006
Posts: 1739
Followers: 1

Kudos [?]: 46 [0], given: 0

Let x be he number of employees before July 1st
And A be the average salary
Then total = xA

After July 1st , number of employees = 9x/10
And Average salary is =11A/10

New total = 99xA/100

Percent = 99xA/100/xA * 100 = 99
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