|
Author |
Message |
|
TAGS:
|
|
|
Manager
Joined: 05 Jul 2006
Posts: 200
Followers: 1
Kudos [?]:
1
[0], given: 0
|
On July 1 of last year, the total number of employees at [#permalink]
 02 Aug 2006, 16:53
Question Stats:
0% (00:00) correct
 0% (00:00) wrong based on 0 sessions
On July 1 of last year, the total number of employees at Company E was decreased by 10%. Without any change in salaries of the remaining employees, the average (arithmetic mean) employee salary was 10% more than after the decrease in number of employees than before the decrase. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent of that before July 1 last year?
A.90%
B.99%
C.100%
D.101%
E.110%
|
|
|
|
|
|
|
VP
Joined: 02 Jun 2006
Posts: 1278
Followers: 2
Kudos [?]:
15
[0], given: 0
|
B.99%
Savg = Sum/E
After decrease
1.1Savg = Sum'/0.9E
=> Sum' = 11/10 x Savg x 9/10
=> Sum' = 0.99Sum
Answer: B. 99%
|
|
|
|
|
|
Manager
Joined: 25 Jul 2006
Posts: 99
Followers: 1
Kudos [?]:
1
[0], given: 0
|
B....
# of people before = 100
salary before = 10
Total salary = 1000
# of people after = 90
salary after = 11
Total salary = 990
% = 990/1000 = 99%
|
|
|
|
|
|
SVP
Joined: 30 Mar 2006
Posts: 1744
Followers: 1
Kudos [?]:
12
[0], given: 0
|
Let x be he number of employees before July 1st
And A be the average salary
Then total = xA
After July 1st , number of employees = 9x/10
And Average salary is =11A/10
New total = 99xA/100
Percent = 99xA/100/xA * 100 = 99
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
close
