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On level farmland, two runners leave at the same time from

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On level farmland, two runners leave at the same time from [#permalink] New post 29 Apr 2010, 05:07
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On level farmland, two runners leave at the same time from the intersection of two country roads. One runner jogs due north at a constant rate of 8 miles per hour while the second runner jogs due east at a constant rate that is 4 miles per hour faster than the first runner's rate. How far apart, to the nearest mile, will they be after hour ?
(A) 6
(B) 7
(C) 8
(D) 12
(E) 14
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Re: farmland [#permalink] New post 29 Apr 2010, 05:47
lanka1 wrote:
On level farmland, two runners leave at the same time from the intersection of two country roads. One runner jogs due north at a constant rate of 8 miles per hour while the second runner jogs due east at a constant rate that is 4 miles per hour faster than the first runner's rate. How far apart, to the nearest mile, will they be after hour ?
(A) 6
(B) 7
(C) 8
(D) 12
(E) 14


is the question correct as none of the options seem fit??
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Re: farmland [#permalink] New post 29 Apr 2010, 06:14
We need to find root (8^2 + 12^2) = root(208)
Since 208 is closer to 196, which is 14^2, my answer is 14 miles corrected to the nearest mile.

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Re: farmland [#permalink] New post 29 Apr 2010, 08:06
1st Runner; 8mph North
2nd Runner; 1st Runner+4mph = 12mph East.

After an hr, 1st runner and 2nd runner will reach 8m and 12m respectively from the intersection they started. Because they ran North and East, their path forms a right angle and hence distance between them would be hypotenuse, which is sqrt(8*8+12*12) = sqrt(208), which is close to 14 (sqrt of 196).

Answer is E.
Re: farmland   [#permalink] 29 Apr 2010, 08:06
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