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Re: On MNP, MN is perpendicular to MP, MP = 24, and NP = 26. What is the a [#permalink]
Skywalker18 wrote:
In right angled \(\triangle\) NMP
NM^2 = NP^2 - MP^2
= 26^2 - 24^2
=676 - 576
= 100
NM= 10

area of \(\triangle\) MNP = 1/2 *NM *MP
= 1/2 *10 * 24
= 120

Answer C

yes Answer is 120 [C]
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Re: On MNP, MN is perpendicular to MP, MP = 24, and NP = 26. What is the a [#permalink]
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Bunuel wrote:

On MNP, MN is perpendicular to MP, MP = 24, and NP = 26. What is the area of MNP in square units?

A. 312
B. 240
C. 120
D. 60
E. 30

Attachment:
2016-01-24_1653.png


It is good to remember the first few pythagorean triplets and their multiples.
Note that 24 and 26 are second positive multiplies of 12 and 13. So this must be the 5, 12, 13 triplet. The third side must be 5*2 = 10

Area of MNP = (1/2)*10*24 = 120 square units.

Answer (C)
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Re: On MNP, MN is perpendicular to MP, MP = 24, and NP = 26. What is the a [#permalink]
Skywalker18 wrote:
In right angled \(\triangle\) NMP
NM^2 = NP^2 - MP^2
= 26^2 - 24^2
=676 - 576
= 100
NM= 10


I like to think of this step as
= 26^2 - 24^2
= (26 - 24)(26 + 24)
=2*50
=100

I find it saves time
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Re: On MNP, MN is perpendicular to MP, MP = 24, and NP = 26. What is the a [#permalink]
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