Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: wats this mean? [#permalink]
28 Aug 2008, 08:45

1

This post received KUDOS

1

This post was BOOKMARKED

arjtryarjtry wrote:

On the coordinate plane is point (0, 0) closer to point (u, v) than to point (u, v + 1) ?

1.v + u^2 = -1 2. v < 0

OA is A. but sorry, i didnt understand this ...

Boss don't post OA .. GIVE A CHANCE TO OTHERS.

Distance between (0, 0) and (u, v) = sqrt {u^2+v^2 } Distance between (0, 0) and (u, v+1) = sqrt {u^2+v^2 +2v+1}

1.v + u^2 = -1 --> u^2 = -1-v ( u^2 is alwasy positive.. So.. v must be -ve and <-1) 2v+1 --> -ve sqrt {u^2+v^2 +2v+1} is alwasy less than sqrt {u^2+v^2 } _________________

Your attitude determines your altitude Smiling wins more friends than frowning

Last edited by x2suresh on 29 Aug 2008, 05:27, edited 1 time in total.

Re: wats this mean? [#permalink]
28 Aug 2008, 10:33

x2suresh wrote:

arjtryarjtry wrote:

On the coordinate plane is point (0, 0) closer to point (u, v) than to point (u, v + 1) ?

1.v + u^2 = -1 2. v < 0

OA is A. but sorry, i didnt understand this ...

Boss don't post OA .. GIVE CHANCE TO OTHERS.

Distance between (0, 0) and (u, v) = sqrt {u^2+v^2 } Distance between (0, 0) and (u, v+1) = sqrt {u^2+v^2 +2v+1}

1.v + u^2 = -1 --> u^2 = -1-v ( u^2 is alwasy positive.. So.. v must be -ve and <-1) 2v+1 --> -ve sqrt {u^2+v^2 +2v+1} is alwasy less than sqrt {u^2+v^2 }

Why will S2 not work? What is the OA? _________________

To find what you seek in the road of life, the best proverb of all is that which says: "Leave no stone unturned." -Edward Bulwer Lytton

Re: wats this mean? [#permalink]
28 Aug 2008, 10:50

leonidas wrote:

x2suresh wrote:

arjtryarjtry wrote:

On the coordinate plane is point (0, 0) closer to point (u, v) than to point (u, v + 1) ?

1.v + u^2 = -1 2. v < 0

OA is A. but sorry, i didnt understand this ...

Boss don't post OA .. GIVE CHANCE TO OTHERS.

Distance between (0, 0) and (u, v) = sqrt {u^2+v^2 } Distance between (0, 0) and (u, v+1) = sqrt {u^2+v^2 +2v+1}

1.v + u^2 = -1 --> u^2 = -1-v ( u^2 is alwasy positive.. So.. v must be -ve and <-1) 2v+1 --> -ve sqrt {u^2+v^2 +2v+1} is alwasy less than sqrt {u^2+v^2 }

Re: wats this mean? [#permalink]
29 Aug 2008, 00:44

Expert's post

1

This post was BOOKMARKED

Let's consider each statement carefully:

a) On the coordinate plane is point (0, 0) closer to point (u, v) than to point (u, v + 1) ? First of all, u does not influence on answer. Therefore, we can restate: On the coordinate line is point (0) closer to point (v) than to point (v + 1) ? Now, we can translate it to language of formulas: |v|<|v+1| Eventually, we can write: v>-0.5

Re: wats this mean? [#permalink]
29 Aug 2008, 02:44

thanks , but how did u get 2 from 1?? could not quite understand...

walker wrote:

Let's consider each statement carefully:

a) On the coordinate plane is point (0, 0) closer to point (u, v) than to point (u, v + 1) ? First of all, u does not influence on answer. Therefore, we can restate: On the coordinate line is point (0) closer to point (v) than to point (v + 1) ? Now, we can translate it to language of formulas: |v|<|v+1|......(1) Eventually, we can write: v>-0.5....(2)

Re: On the coordinate plane is point (0, 0) closer to point (u, [#permalink]
13 May 2014, 23:51

1

This post received KUDOS

Expert's post

arjtryarjtry wrote:

On the coordinate plane is point (0, 0) closer to point (u, v) than to point (u, v + 1) ?

(1) v + u^2 = -1

(2) v < 0

M22-11

On the coordinate plane is point (0, 0) closer to point (u, v) than to point (u, v + 1) ?

The formula to calculate the distance between two points (x_1,y_1) and (x_2,y_2) is d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}.

So basically the question asks whether the distance between the points (0, 0) and (u, v) is less than the distance between the points (0, 0) and (u, v + 1): is \sqrt{(u-0)^2+(v-0)^2}<\sqrt{(u-0)^2+(v+1-0)^2}? --> is \sqrt{u^2+v^2}<\sqrt{u^2+(v+1)^2}? --> is u^2+v^2<u^2+v^2+2v+1? --> is v>-\frac{1}{2}?

(1) v + u^2 = -1 --> v=-1-u^2\leq{-1} --> so the answer to the question is NO. Sufficient.