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But I think it should be "C", how about this? (I many be wrong)
If we consider only statement2; r, s itself can be negative & -s can be positive, it means -s can be on the opposite side of r & s.
The stems basically asks is s = -r ? In other words, if zero is exactly between the two, then one is the negative value of the other. Draw a number line to visualize this.
Stmnt 1:
Nothing is said about the property of r. Insufficient.
Stmnt 2:
The distance b/w t and r is the same as the distance b/w t and -s. In other words,
I eliminated this possibility in the test, but I think that was due to test pressure. Your logic looks correct...B gives two possibilites => r,s < 0 or r<0 and s > 0.
vivek123 wrote:
Me too selected B.
But I think it should be "C", how about this? (I many be wrong) If we consider only statement2; r, s itself can be negative & -s can be positive, it means -s can be on the opposite side of r & s.
s = -5 => -s = 5, r = -5 and t = 0.......................One possibility
lhotseface, vivek and others... s =5, r = -5 and t = 10............Second possibility
What if t =0 and r=5 and s =5... that leads us to E!!
My take on this:
If we are shown 3 numbers on a number line at distinct locations, we should assume that they are not equal and that they have a relationship defined by their corresponding locations. So from the picture I would assume r < s < t
That leaves us with B as the unambiguous answer. Any thoughts? _________________
"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."
That is what I thought on the test...but the OA is C from GMATPrep. (?!)
In the real exam, I am going to assume such ambiguous questions are experimental, pick a reasonable choice and move on.
giddi77 wrote:
lhotseface wrote:
s = -5 => -s = 5, r = -5 and t = 0.......................One possibility
lhotseface, vivek and others... s =5, r = -5 and t = 10............Second possibility
What if t =0 and r=5 and s =5... that leads us to E!!
My take on this: If we are shown 3 numbers on a number line at distinct locations, we should assume that they are not equal and that they have a relationship defined by their corresponding locations. So from the picture I would assume r < s < t
That leaves us with B as the unambiguous answer. Any thoughts?
What if t =0 and r=5 and s =5... that leads us to E!!
t cannot be zero since s is right to the zero.
giddi77 wrote:
If we are shown 3 numbers on a number line at distinct locations, we should assume that they are not equal and that they have a relationship defined by their corresponding locations. So from the picture I would assume r < s < t
IMO, in GMAT, unless figures are not supported by the facts, figures are not drawn to scale. therefore, it is possible that the value of r, s and t could be anything.
lhotseface wrote:
On the number line <-----------r-------s-----------t--------------->
Is zero halfway between r and s ?
1. s is to the right of zero. 2. The distance b/w t and r is the same as the distance b/w t and -s.
from i, s is +ve. so not suff.
from ii, if the distance between t and r is the same as the distance between t and -s, then r must equal to s. cuz the distance between any given points is absolute.
so to have the distance between t and s = distance between t and -s, s and r must have the same value. if so then we can say that o is not a halfway between r and s.
From 1) We know that t-r=t-(-s) => s=-r But it's possible that s=-r=0 so we can't say whether 0 on a halfwat
From 2) we know that C is NOT zero thus from s=-r we know that r is a not zero negative number while C is not zero positive number
So it's C