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On the number line above, p, q, r, s, and t are five consec

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On the number line above, p, q, r, s, and t are five consec [#permalink] New post 07 Dec 2012, 07:30
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On the number line above, p, q, r, s, and t are five consecutive even integers in increasing order. What is the average (arithmetic mean) of these five integers?

(1) q + s =24
(2) The average (arithmetic mean) of q and r is 11.
[Reveal] Spoiler: OA
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Re: On the number line above, p, q, r, s, and t are five consec [#permalink] New post 07 Dec 2012, 07:37
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On the number line above, p, q, r, s, and t are five consecutive even integers in increasing order. What is the average (arithmetic mean) of these five integers?

{p, q, r, s, t} is an evenly spaced set thus its mean = median = middle term = r.

(1) q + s =24. Since q, r and s are consecutive even integers, then q=r-2 and s=r+2 --> (r-2)+(r+2)=24 --> r=12. Sufficient.

(2) The average (arithmetic mean) of q and r is 11. (r-2)+r=2*11 --> r=12. Sufficient.

Answer: D.
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Re: On the number line above, p, q, r, s, and t are five consec [#permalink] New post 10 Dec 2012, 07:26
which is the level of the question? 500? tks a lot :)
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Re: On the number line above, p, q, r, s, and t are five consec [#permalink] New post 10 Dec 2012, 07:42
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fabrizio1983 wrote:
which is the level of the question? 500? tks a lot :)


I'd say it's ~600.

P.S. You can see the difficulty level of a question in the first post where the tags are (TAGS: Difficulty: 600-700 Level).
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Re: On the number line above, p, q, r, s, and t are five consec [#permalink] New post 11 Dec 2012, 03:54
Walkabout wrote:
Attachment:
Number line.png
On the number line above, p, q, r, s, and t are five consecutive even integers in increasing order. What is the average (arithmetic mean) of these five integers?

(1) q + s =24
(2) The average (arithmetic mean) of q and r is 11.


Ans. : Let p=x, q=x+2, r=x+4 , s=x+6, t=x+8 to find the mean we need to find x.
From statement 1 , we get 2x+8=24
From statement 2 we get x+3=11
Therefore the answer is (D).
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Re: On the number line above, p, q, r, s, and t are five consec [#permalink] New post 16 Dec 2012, 12:38
My understanding of consecutive integers, is that they are separated by only 1, i.e. 3, 4, 5, 6, 7, 8

I was able to find the first statement sufficient, but not the second, mainly because the answer uses the formula p + (p+2) +....

Why is 2 being added to P?
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Re: On the number line above, p, q, r, s, and t are five consec [#permalink] New post 16 Dec 2012, 22:41
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kelleygrad05 wrote:
My understanding of consecutive integers, is that they are separated by only 1, i.e. 3, 4, 5, 6, 7, 8

I was able to find the first statement sufficient, but not the second, mainly because the answer uses the formula p + (p+2) +....

Why is 2 being added to P?


We are not told that p, q, r, s, and t are consecutive integers. We are given that p, q, r, s, and t are five consecutive EVEN integers. For example 2, 4, 6, 8, 10.
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Re: On the number line above, p, q, r, s, and t are five consec [#permalink] New post 11 Jan 2014, 09:17
They are basically giving us some equation in disguise.

1. q+s=24 but for a fact set we know that the leap between q and s is 4 and this translates into an equation that subtracted gives us the value of q from which we can calculate the average.
2. q+r=22 same old story, the leap between q and r this time is 2 units. r-q=2 subtract it from the given equation and you are done you got one value, the remaining values follow logically.

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Re: On the number line above, p, q, r, s, and t are five consec   [#permalink] 11 Jan 2014, 09:17
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