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On the number line, the distance between x and y is greater

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VP
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On the number line, the distance between x and y is greater [#permalink] New post 28 Dec 2007, 09:23
On the number line, the distance between x and y is greater than the distance between x and z. Does z lie between x and y on the number line?

1. xyz<0
2. xy<0
Senior Manager
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Re: number line [#permalink] New post 28 Dec 2007, 09:35
marcodonzelli wrote:
On the number line, the distance between x and y is greater than the distance between x and z. Does z lie between x and y on the number line?

1. xyz<0
2. xy<0


(1) xyz<0 x,y,z all -ve or two +ve 1 -ve we donot know wich one is -ve (insuff)

(2) xy<0 either x or y is -ve that means x and y are on either side of 0


x----0---------y or y------0---------x

x---0---z----y or z---x--0----y (insuff)

Togather

Since z has to be +ve because
x+ve y -ve z +ve
x-ve y+ve z+ve

SO x---0---z----y or z---x--0----y are possible or
y---0---z---x or y---0----x---z is also possible

INSUFF
Answer E
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 [#permalink] New post 28 Dec 2007, 09:37
Expert's post
E


y____0________z1_____x_____z2

y<0
x>0
z1,z2>0 - two possible positions of z.

x,y,z1 and x,y,z2 satisfy 1 and 2 condition but we can not answer the question.
VP
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 [#permalink] New post 28 Dec 2007, 09:42
let's try c...

XYZ + XY <0

XY(Z+1)<0>-1 and one between x and y is negative...but since we do not know the exact position of x and y...OA is E
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 [#permalink] New post 28 Dec 2007, 11:19
Im getting E

Stat 1 says that one of the values , or all three, are negative. They dont give any info to determine the specific position of x, y or z. Insufficient

Stat 2 says that x or y are negative, but not which is which.

Together, all we know is that z must be negative. Thats fine, but we still dont know about its position relative to x and y.
  [#permalink] 28 Dec 2007, 11:19
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On the number line, the distance between x and y is greater

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