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# One bag contains 4 white balls and 2 black balls , another

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Manager
Joined: 27 Jul 2003
Posts: 124
Location: Singapore
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One bag contains 4 white balls and 2 black balls , another [#permalink]  09 Oct 2003, 20:11
One bag contains 4 white balls and 2 black balls , another bag contains 3 white balls and 5 black balls . if one ball is drawn from each bag, determine the probability p that
a. both are white
b. both are black
c. 1 is white and 1 is black
CEO
Joined: 15 Aug 2003
Posts: 3467
Followers: 61

Kudos [?]: 705 [0], given: 781

Re: white Balls / Black Balls [#permalink]  09 Oct 2003, 21:53
araspai wrote:
One bag contains 4 white balls and 2 black balls , another bag contains 3 white balls and 5 black balls . if one ball is drawn from each bag, determine the probability p that
a. both are white
b. both are black
c. 1 is white and 1 is black

a. both are white : 4/6 * 3/8 = 1/4
b. both are black : 2/6 * 5/8 = 5/24
c. 1 is white and 1 is black : 4/6*5/8 + 2/6*3/8 = 26/48 = 13/24

EDIT : c) was edited.

Last edited by Praetorian on 14 Oct 2003, 00:05, edited 1 time in total.
SVP
Joined: 03 Feb 2003
Posts: 1608
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Kudos [?]: 78 [0], given: 0

a. agree
b. agree
c. P=P(BW)+P(WB)=2/6*3/8+4/6*5/8=10/12=13/24

EDIT

Last edited by stolyar on 14 Oct 2003, 00:56, edited 1 time in total.
CEO
Joined: 15 Aug 2003
Posts: 3467
Followers: 61

Kudos [?]: 705 [0], given: 781

stolyar wrote:
a. agree
b. agree
c. P=P(BW)+P(WB)=4/6*5/8+5/8*4/6=10/12=5/6

Quote:
4/6*5/8+5/8*4/6

where you get the bold part from...

i edited my solution...see if its ok.

thanks
praetorian
SVP
Joined: 03 Feb 2003
Posts: 1608
Followers: 6

Kudos [?]: 78 [0], given: 0

I have also redacted my solution.
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