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One bag contains 4 white balls and 2 black balls , another

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Manager
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One bag contains 4 white balls and 2 black balls , another [#permalink]

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New post 09 Oct 2003, 20:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

One bag contains 4 white balls and 2 black balls , another bag contains 3 white balls and 5 black balls . if one ball is drawn from each bag, determine the probability p that
a. both are white
b. both are black
c. 1 is white and 1 is black
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New post 09 Oct 2003, 21:53
araspai wrote:
One bag contains 4 white balls and 2 black balls , another bag contains 3 white balls and 5 black balls . if one ball is drawn from each bag, determine the probability p that
a. both are white
b. both are black
c. 1 is white and 1 is black


a. both are white : 4/6 * 3/8 = 1/4
b. both are black : 2/6 * 5/8 = 5/24
c. 1 is white and 1 is black : 4/6*5/8 + 2/6*3/8 = 26/48 = 13/24

EDIT : c) was edited.

Last edited by Praetorian on 14 Oct 2003, 00:05, edited 1 time in total.
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New post 13 Oct 2003, 23:58
a. agree
b. agree
c. P=P(BW)+P(WB)=2/6*3/8+4/6*5/8=10/12=13/24

EDIT

Last edited by stolyar on 14 Oct 2003, 00:56, edited 1 time in total.
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New post 14 Oct 2003, 00:07
stolyar wrote:
a. agree
b. agree
c. P=P(BW)+P(WB)=4/6*5/8+5/8*4/6=10/12=5/6



Quote:
4/6*5/8+5/8*4/6


where you get the bold part from...

i edited my solution...see if its ok.

thanks
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New post 14 Oct 2003, 00:56
I have also redacted my solution.
  [#permalink] 14 Oct 2003, 00:56
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