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One computer can upload 100 megabytes worth of data in 6 [#permalink]
20 Mar 2012, 11:17

00:00

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Difficulty:

15% (low)

Question Stats:

89% (02:17) correct
10% (03:22) wrong based on 163 sessions

One computer can upload 100 megabytes worth of data in 6 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 42 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data?

(A) 6 (B) 7 (C) 9 (D) 11 (E) 13

This is how I am trying to solve this question:

Let say A be the computer 1 and B be the computer 2

Computer A 1 second work : 100/6 Computer A + Computer B 1 second work : 1300/42

1/A + 1/B = AB/A+B

We have to find 1/B. I struggle to complete this question.

Re: One computer can upload 100 megabytes worth of data in 6 [#permalink]
20 Mar 2012, 13:53

3

This post received KUDOS

Expert's post

enigma123 wrote:

One computer can upload 100 megabytes worth of data in 6 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 42 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data?

(A) 6 (B) 7 (C) 9 (D) 11 (E) 13

This is how I am trying to solve this question:

Let say A be the computer 1 and B be the computer 2

Computer A 1 second work : 100/6 Computer A + Computer B 1 second work : 1300/42

1/A + 1/B = AB/A+B

We have to find 1/B. I struggle to complete this question.

Since the first computer can upload 100 megabytes worth of data in 6 seconds then in 6*7=42 seconds it can upload 7*100=700 megabytes worth of data, hence the second compute in 42 seconds uploads 1300-700=600 megabytes worth of data. The second computer can upload 600/6=100 megabytes of data in 42/6=7 seconds.

One computer can upload 100 megabytes worth of data in 6 [#permalink]
04 Mar 2013, 06:10

One computer can upload 100 megabytes worth of data in 6 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 42 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data?

Re: One computer can upload 100 megabytes worth of data in 6 [#permalink]
04 Mar 2013, 06:28

1

This post received KUDOS

The given computer can upload 100 MB of data in 6 seconds => In 42 seconds, it will upload 100 MB x 7 = 700 MB of data

In 42 seconds, the two computers working together upload 1300 MB of data => The other computer uploads 600 MB (1300-700 MB) of data in 42 seconds => The other computer uploads 100 MB of data in 42/6 = 7 seconds

Re: One computer can upload 100 megabytes worth of data in 6 [#permalink]
04 Mar 2013, 10:57

Expert's post

megafan wrote:

One computer can upload 100 megabytes worth of data in 6 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 42 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data?

(A) 6 (B) 7 (C) 9 (D) 11 (E) 13

Source: Gmat Hacks 1800

Merging similar topics. Please refer to the solutions above.
_________________

Rate (Computer in question) = 1300/42 - 100/6 = 100/7

Rate * Time = Work

100/7 * Time =100

Time =7
_________________

Rgds, TGC! _____________________________________________________________________ I Assisted You => KUDOS Please _____________________________________________________________________________

gmatclubot

Re: One computer can upload 100 megabytes worth of data in 6
[#permalink]
27 Sep 2013, 22:41