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One computer can upload 100 megabytes worth of data in 6

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One computer can upload 100 megabytes worth of data in 6 [#permalink] New post 20 Mar 2012, 11:17
00:00
A
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  15% (low)

Question Stats:

89% (02:17) correct 10% (03:22) wrong based on 163 sessions
One computer can upload 100 megabytes worth of data in 6 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 42 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data?

(A) 6
(B) 7
(C) 9
(D) 11
(E) 13

This is how I am trying to solve this question:

Let say A be the computer 1 and B be the computer 2

Computer A 1 second work : 100/6
Computer A + Computer B 1 second work : 1300/42

1/A + 1/B = AB/A+B

We have to find 1/B. I struggle to complete this question.
[Reveal] Spoiler: OA

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Re: Two computers [#permalink] New post 20 Mar 2012, 11:22
Quote:
This is how I am trying to solve this question:

Let say A be the computer 1 and B be the computer 2

Computer A 1 second work : 100/6
Computer A + Computer B 1 second work : 1300/42

1/A + 1/B = AB/A+B

We have to find 1/B. I struggle to complete this question.


You are on the right track..

So Computer B's rate = 1300/42-100/6 = 600/42

So computer B can upload 600MB in 42 seconds.. divide numerator and denominator by 6 and you get 100/7 so 2nd computer takes 7 seconds to upload 100MB
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Re: One computer can upload 100 megabytes worth of data in 6 [#permalink] New post 20 Mar 2012, 13:53
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Expert's post
enigma123 wrote:
One computer can upload 100 megabytes worth of data in 6 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 42 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data?

(A) 6
(B) 7
(C) 9
(D) 11
(E) 13

This is how I am trying to solve this question:

Let say A be the computer 1 and B be the computer 2

Computer A 1 second work : 100/6
Computer A + Computer B 1 second work : 1300/42

1/A + 1/B = AB/A+B

We have to find 1/B. I struggle to complete this question.


Since the first computer can upload 100 megabytes worth of data in 6 seconds then in 6*7=42 seconds it can upload 7*100=700 megabytes worth of data, hence the second compute in 42 seconds uploads 1300-700=600 megabytes worth of data. The second computer can upload 600/6=100 megabytes of data in 42/6=7 seconds.

Answer: B.
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Re: One computer can upload 100 megabytes worth of data in 6 [#permalink] New post 07 Apr 2012, 04:56
enigma123 wrote:

This is how I am trying to solve this question:

Let say A be the computer 1 and B be the computer 2

Computer A 1 second work : 100/6
Computer A + Computer B 1 second work : 1300/42

1/A + 1/B = AB/A+B

We have to find 1/B. I struggle to complete this question.


A needs 6sec for 100 ; A+B need 42 sec for 1300 or 100*42/1300=42/13 sec for 100

so now we have

rate of A for 100 is 1/6
rate of B for 100 is 1/x
rate of (a+b) for 100 is 13/42

1/6+1/x=13/42
x=7 sec

hope it helps :)
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Re: One computer can upload 100 megabytes worth of data in 6 [#permalink] New post 13 Apr 2012, 02:52
RT=W
(100/6+X)*42=1300 --> 42X=600 --> X=600/42 rate of the second machine
600/42*t=100 --> t=7 sec. needs the second machine to upload data
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Re: One computer can upload 100 megabytes worth of data in 6 [#permalink] New post 15 Nov 2012, 22:29
Setup the rate equations. This always help.

rate-first=\frac{1}{A}=\frac{100}{6sec}
rate-together=\frac{1}{A}+\frac{1}{B}=\frac{1300}{42}

rate-together - rate-first = rate-second

\frac{1}{A}+\frac{1}{B}-\frac{1}{A}=\frac{1300}{42}-\frac{100}{6}=\frac{600}{42}=\frac{100}{7secs}

Answer: B
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One computer can upload 100 megabytes worth of data in 6 [#permalink] New post 04 Mar 2013, 06:10
One computer can upload 100 megabytes worth of data in 6 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 42 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data?

(A) 6
(B) 7
(C) 9
(D) 11
(E) 13

Source: Gmat Hacks 1800
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Re: One computer can upload 100 megabytes worth of data in 6 [#permalink] New post 04 Mar 2013, 06:25
http://www.youtube.com/watch?v=bf9ROHLJNSA
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Re: One computer can upload 100 megabytes worth of data in 6 [#permalink] New post 04 Mar 2013, 06:28
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The given computer can upload 100 MB of data in 6 seconds
=> In 42 seconds, it will upload 100 MB x 7 = 700 MB of data

In 42 seconds, the two computers working together upload 1300 MB of data
=> The other computer uploads 600 MB (1300-700 MB) of data in 42 seconds
=> The other computer uploads 100 MB of data in 42/6 = 7 seconds

Option B
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Re: One computer can upload 100 megabytes worth of data in 6 [#permalink] New post 04 Mar 2013, 10:57
Expert's post
megafan wrote:
One computer can upload 100 megabytes worth of data in 6 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 42 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data?

(A) 6
(B) 7
(C) 9
(D) 11
(E) 13

Source: Gmat Hacks 1800


Merging similar topics. Please refer to the solutions above.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: One computer can upload 100 megabytes worth of data in 6 [#permalink] New post 27 Sep 2013, 22:41
Shouldn't be a 700 level problem.

Rate (1 computer) = 100/6
Rate ( 2 computers) = 1300/42

Rate (Computer in question) = 1300/42 - 100/6 = 100/7

Rate * Time = Work

100/7 * Time =100

Time =7
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Re: One computer can upload 100 megabytes worth of data in 6   [#permalink] 27 Sep 2013, 22:41
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