One-fourth of a solution that was 10% by weight was replaced : GMAT Problem Solving (PS)
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 23 Jan 2017, 20:08

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# One-fourth of a solution that was 10% by weight was replaced

Author Message
TAGS:

### Hide Tags

Senior Manager
Joined: 10 Apr 2012
Posts: 276
Location: United States
Concentration: Technology, Other
GPA: 2.44
WE: Project Management (Telecommunications)
Followers: 5

Kudos [?]: 736 [1] , given: 325

One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

13 Mar 2013, 12:52
1
KUDOS
23
This post was
BOOKMARKED
00:00

Difficulty:

65% (hard)

Question Stats:

59% (02:43) correct 41% (01:53) wrong based on 446 sessions

### HideShow timer Statistics

One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight?

A. 34%
B. 24%
C. 22%
D. 18%
E. 8.5%

[Reveal] Spoiler:
I am trying to solve it using Allegation method , but not quit sure how to get the end result , Please help . Also, elaborate the steps so that I can understand the approach .
many thanks !

I started with 10% ------------ x% in the first row

16% in the second row

and x-16% and 6% in the last one

this gives me x-16/6= ? "stuck here "
[Reveal] Spoiler: OA

Last edited by Bunuel on 14 Mar 2013, 01:15, edited 1 time in total.
Edited the question.
Intern
Joined: 28 Jan 2013
Posts: 8
Location: United States
Concentration: Strategy, Technology
GMAT Date: 04-20-2013
GPA: 3.2
WE: Analyst (Computer Software)
Followers: 0

Kudos [?]: 14 [4] , given: 4

Re: One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

13 Mar 2013, 17:30
4
KUDOS
1
This post was
BOOKMARKED
guerrero25 wrote:
One-fourth of a solution that was 10% by weight was replaced by a second solution resulting in a solution that was 16% sugar by weight. The second solution was what percent sugar by weight.

34%
24%
22%
18%
8.5%

I am trying to solve it using Allegation method , but not quit sure how to get the end result , Please help . Also, elaborate the steps so that I can understand the approach .
many thanks !

I started with 10% ------------ x% in the first row

16% in the second row

and x-16% and 6% in the last one

this gives me x-16/6= ? "stuck here "

This is the first question I trying to explain here, so please bear with my mistakes.

The best I could think of solving this is using nos.

Lets say we have a 100 ml of solution and it has 10 gm of sugar.

100 ml ---- 10 gm
75 ml ------- 7.5 gm
25 ml ------- 2.5 gm

Once we remove 25 ml, we have only 7.5 gm sugar left to make 16% of 100 ml solution we need 8.5 gm more sugar.
so we need 8.5 gm in 25 ml, which is 8.5 * 4 = 34 gm/ (25 * 4).

Ans A) 34 %
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7130
Location: Pune, India
Followers: 2140

Kudos [?]: 13706 [7] , given: 222

Re: One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

13 Mar 2013, 19:52
7
KUDOS
Expert's post
8
This post was
BOOKMARKED
guerrero25 wrote:
One-fourth of a solution that was 10% by weight was replaced by a second solution resulting in a solution that was 16% sugar by weight. The second solution was what percent sugar by weight.

34%
24%
22%
18%
8.5%

I am trying to solve it using Allegation method , but not quit sure how to get the end result , Please help . Also, elaborate the steps so that I can understand the approach .
many thanks !

I started with 10% ------------ x% in the first row

16% in the second row

and x-16% and 6% in the last one

this gives me x-16/6= ? "stuck here "

The allegation formula is this:

w1/w2 = (A2 - Aavg)/(Aavg - A1)
w1/w2 is the ratio of weights of the two solutions. Here, since 1/4 of the first solution is replaced, the weight of the first solution is 3/4 and that of the second solution is 1/4 so w1/w2 = 3/1

A2 - Concentration of second solution which we have to find here
Aavg - Concentration of mixture which is 16%
A1 - Concentration of first solution which is 10%

3/1 = (A2 - 16)/(16 - 10)
A2 = 34%

To find out how you get this formula, check: http://www.veritasprep.com/blog/2011/03 ... -averages/
For more on mixtures and replacement, check:
http://www.veritasprep.com/blog/2011/04 ... -mixtures/
http://www.veritasprep.com/blog/2012/01 ... -mixtures/
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Director Status: Done with formalities.. and back.. Joined: 15 Sep 2012 Posts: 647 Location: India Concentration: Strategy, General Management Schools: Olin - Wash U - Class of 2015 WE: Information Technology (Computer Software) Followers: 47 Kudos [?]: 549 [6] , given: 23 Re: One-fourth of a solution that was 10% by weight was replaced [#permalink] ### Show Tags 13 Mar 2013, 21:22 6 This post received KUDOS guerrero25 wrote: One-fourth of a solution that was 10% by weight was replaced by a second solution resulting in a solution that was 16% sugar by weight. The second solution was what percent sugar by weight. 34% 24% 22% 18% 8.5% I am trying to solve it using Allegation method , but not quit sure how to get the end result , Please help . Also, elaborate the steps so that I can understand the approach . many thanks ! Instead of using complex calculations and remembering formulae, why dont u directly get to weighted average. 3 parts of 10% + 1 part of x (unknown) % = 4 parts of 16% => x% = 64%-30% = 34% ans A it is. _________________ Lets Kudos!!! Black Friday Debrief Math Expert Joined: 02 Sep 2009 Posts: 36618 Followers: 7102 Kudos [?]: 93589 [4] , given: 10578 Re: One-fourth of a solution that was 10% by weight was replaced [#permalink] ### Show Tags 14 Mar 2013, 01:16 4 This post received KUDOS Expert's post 3 This post was BOOKMARKED One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight? A. 34% B. 24% C. 22% D. 18% E. 8.5% This is a weighted average question. Say the second solution (which was 1/4 th of total) was x% sugar, then 3/4*0.1+1/4*x=1*0.16 --> x=0.34. Alternately you can consider total solution to be 100 liters and in this case you'll have: 75*0.1+25*x=100*0.16 --> x=0.34. Answer: A. Hope it helps. _________________ Senior Manager Joined: 10 Apr 2012 Posts: 276 Location: United States Concentration: Technology, Other GPA: 2.44 WE: Project Management (Telecommunications) Followers: 5 Kudos [?]: 736 [0], given: 325 Re: One-fourth of a solution that was 10% by weight was replaced [#permalink] ### Show Tags 14 Mar 2013, 08:51 Thank you all for helping me understand the problem . Now I am getting a good grip on the concepts .The members /experts here 're truly amazing ! Kudos all Regards! Intern Joined: 10 Sep 2013 Posts: 17 Location: India Concentration: Strategy GMAT 1: 700 Q50 V34 GPA: 3.8 WE: General Management (Energy and Utilities) Followers: 0 Kudos [?]: 7 [0], given: 0 Re: One-fourth of a solution that was 10% by weight was replaced [#permalink] ### Show Tags 17 Sep 2013, 04:38 One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight? A. 34% B. 24% C. 22% D. 18% E. 8.5% let the volume of the original solution be X and p be the percentage of sugar in the solution which is replaced. then 10*3x/4 + p*1x/4 = 16*x => 30 + p = 64 => p = A Intern Joined: 06 Feb 2012 Posts: 16 Followers: 0 Kudos [?]: 40 [0], given: 7 Re: One-fourth of a solution that was 10% by weight was replaced [#permalink] ### Show Tags 21 Oct 2013, 02:41 Vips0000 wrote: guerrero25 wrote: One-fourth of a solution that was 10% by weight was replaced by a second solution resulting in a solution that was 16% sugar by weight. The second solution was what percent sugar by weight. 34% 24% 22% 18% 8.5% I am trying to solve it using Allegation method , but not quit sure how to get the end result , Please help . Also, elaborate the steps so that I can understand the approach . many thanks ! Instead of using complex calculations and remembering formulae, why dont u directly get to weighted average. 3 parts of 10% + 1 part of x (unknown) % = 4 parts of 16% => x% = 64%-30% = 34% ans A it is. thanks m8 that really helped. clear and easy Current Student Joined: 06 Sep 2013 Posts: 2035 Concentration: Finance GMAT 1: 770 Q0 V Followers: 62 Kudos [?]: 594 [0], given: 355 Re: One-fourth of a solution that was 10% by weight was replaced [#permalink] ### Show Tags 16 Dec 2013, 15:05 guerrero25 wrote: One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight? A. 34% B. 24% C. 22% D. 18% E. 8.5% [Reveal] Spoiler: I am trying to solve it using Allegation method , but not quit sure how to get the end result , Please help . Also, elaborate the steps so that I can understand the approach . many thanks ! I started with 10% ------------ x% in the first row 16% in the second row and x-16% and 6% in the last one this gives me x-16/6= ? "stuck here " By differentials too So basically we need to find the % of sugar by weight of the second solution. We have this for the first solution 10% and we have the ratio of both and that the final solution was 16%. So then since only 25% (1/4) is being replace the unknown percentage has a weight of 1 while the original amount remains with a weight of 3 (Thus the ratio 3:1). So by applying the differences between the result of 16% and each point value we can solve for ‘x’, in this case the percentage of sugar in the second solution 3(-6) + (x-16) = 0 -18 + x -16 = 0 X= 34 Hence (A) is the answer Hope it helps Cheers! J Director Joined: 03 Aug 2012 Posts: 916 Concentration: General Management, General Management GMAT 1: 630 Q47 V29 GMAT 2: 680 Q50 V32 GPA: 3.7 WE: Information Technology (Investment Banking) Followers: 23 Kudos [?]: 696 [1] , given: 322 Re: One-fourth of a solution that was 10% by weight was replaced [#permalink] ### Show Tags 19 Apr 2014, 05:41 1 This post received KUDOS Alligation is the KEY 3/4 of 10%------------------------------1/4 of X% -------------------16%---------------------------- (X-16)%------------------------------------------6% (X-16)/6=3/1 X=34% _________________ Rgds, TGC! _____________________________________________________________________ I Assisted You => KUDOS Please _____________________________________________________________________________ Manager Joined: 22 Feb 2009 Posts: 229 Followers: 5 Kudos [?]: 133 [0], given: 148 Re: One-fourth of a solution that was 10% by weight was replaced [#permalink] ### Show Tags 04 Aug 2014, 21:46 TGC wrote: Alligation is the KEY 3/4 of 10%------------------------------1/4 of X% -------------------16%---------------------------- (X-16)%------------------------------------------6% (X-16)/6=3/1 X=34% Is it called cross method? I think it is the fastest solution _________________ ......................................................................... +1 Kudos please, if you like my post Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7130 Location: Pune, India Followers: 2140 Kudos [?]: 13706 [0], given: 222 Re: One-fourth of a solution that was 10% by weight was replaced [#permalink] ### Show Tags 04 Aug 2014, 23:05 vad3tha wrote: TGC wrote: Alligation is the KEY 3/4 of 10%------------------------------1/4 of X% -------------------16%---------------------------- (X-16)%------------------------------------------6% (X-16)/6=3/1 X=34% Is it called cross method? I think it is the fastest solution This is called Alligation or the scale method (a variant). Read more about this method here: http://www.veritasprep.com/blog/2011/03 ... -averages/ _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

Veritas Prep Reviews

Senior Manager
Joined: 17 Dec 2012
Posts: 447
Location: India
Followers: 26

Kudos [?]: 396 [0], given: 14

One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

04 Aug 2014, 23:50
guerrero25 wrote:
One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight?

A. 34%
B. 24%
C. 22%
D. 18%
E. 8.5%

Original - sugar=0.1*s1, other = 0.9*s1
Removed - sugar= -0.1 * s1/4, other= - 0.9*s1/4
Added - sugar= x * s1/4, other= (1-x)*s1/4
Resultant sugar= 0.16*s1, other=0.84*s1

(0.1*s1 - 0.1*s1/4 + x*s1/4) / (0.9*s1 - 0.9*s1/4 + (1-x)*s1/4) = 16/84
x=0.34 or percent sugar by weight is 34%

The advantage with this approach is that you can use it for any mixture problem.
_________________

Srinivasan Vaidyaraman
Sravna
http://www.sravnatestprep.com

Classroom and Online Coaching

SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1858
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Followers: 47

Kudos [?]: 1937 [1] , given: 193

Re: One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

05 Aug 2014, 02:07
1
KUDOS
Total Solution ........................ Sugar Concentration

100 ............................................ 10
(Assumed)

25% solution removed

100-25 ......................................... $$10-\frac{10}{4}$$

75 ................................................... $$\frac{30}{4}$$

Same quantity has been replaced. Say the new solution sugar weight = x%

75 + 25 ......................................... $$\frac{30}{4} + \frac{25x}{100}$$

Given that the resultant solution has sugar concentration of 16%

So equating the above

$$\frac{30}{4} + \frac{25x}{100} = 16$$

x = 34%

_________________

Kindly press "+1 Kudos" to appreciate

Director
Joined: 23 Jan 2013
Posts: 579
Schools: Cambridge'16
Followers: 1

Kudos [?]: 42 [0], given: 40

One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

24 Oct 2014, 05:20
Differential method

10------16-------x
problem says that 1/4 was replaced by higher concentration solution, meaning that ratio of 10% sol to X% sol was 3:1
16-10=6 --> 6*3=18 ---> 16+18=34% needs to be second solution

Checking

10-----16-----------------34
6x=18y
x/y=18/6=3:1, it is correct

A
Intern
Joined: 04 Jul 2014
Posts: 48
Schools: Smeal
Followers: 0

Kudos [?]: 28 [0], given: 40

One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

25 Oct 2014, 05:45
guerrero25 wrote:
One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight?

A. 34%
B. 24%
C. 22%
D. 18%
E. 8.5%

[Reveal] Spoiler:
I am trying to solve it using Allegation method , but not quit sure how to get the end result , Please help . Also, elaborate the steps so that I can understand the approach .
many thanks !

I started with 10% ------------ x% in the first row

16% in the second row

and x-16% and 6% in the last one

this gives me x-16/6= ? "stuck here "

[img]10% x%
16%
3/4 1/4
3 1
[/img]

The difference 6 obtained by usual cross subtraction is 1 part. So 3 parts is 18 . To get 18, 16 must be subtracted from X. So x is the addition of 16 plus 18

THEREFORE X = 18+16 = 34 %
Manager
Joined: 22 Aug 2014
Posts: 204
Followers: 0

Kudos [?]: 10 [0], given: 49

Re: One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

07 May 2015, 02:23
Vips0000 wrote:
guerrero25 wrote:
One-fourth of a solution that was 10% by weight was replaced by a second solution resulting in a solution that was 16% sugar by weight. The second solution was what percent sugar by weight.
34%
24%
22%
18%
8.5%

I am trying to solve it using Allegation method , but not quit sure how to get the end result , Please help . Also, elaborate the steps so that I can understand the approach .
many thanks !

Instead of using complex calculations and remembering formulae, why dont u directly get to weighted average.

3 parts of 10% + 1 part of x (unknown) % = 4 parts of 16%
=> x% = 64%-30% = 34%

ans A it is.

Thank you!
Your explanation is crisp and clear...kudos to you!
Director
Joined: 07 Dec 2014
Posts: 500
Followers: 3

Kudos [?]: 82 [0], given: 2

One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

26 Aug 2015, 15:54
let x=sugar % of solution 2
.1-.1/4+x/4=.16
x=.34=34%
Director
Joined: 26 Mar 2013
Posts: 681
Followers: 3

Kudos [?]: 134 [0], given: 96

Re: One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

18 Jan 2016, 04:52
This question could be solved with logic and simple calculation.

If we use equal amount of solution with different concentrations, then the resulting concentration is the Mean of concentrations

So, if we apply the same concept above, solution 1 has 10 % and solution 2 need to be 31% to make the resulting concentration 16% ( if both with same amount solutions, for example 75 ml)

To have same resulting concentration 16%, we need to decrease the amount of solution 2 and increase its concentration above 31%.

Manager
Joined: 07 May 2015
Posts: 107
Followers: 0

Kudos [?]: 14 [1] , given: 6

Re: One-fourth of a solution that was 10% by weight was replaced [#permalink]

### Show Tags

18 Jan 2016, 15:02
1
KUDOS
Thank you SO MUCH VeritasPrepKarishma !!! You made this topic look so easy in your blogs below. I am getting all the mixture questions correct now with the help of your blog.

VeritasPrepKarishma wrote:
guerrero25 wrote:
One-fourth of a solution that was 10% by weight was replaced by a second solution resulting in a solution that was 16% sugar by weight. The second solution was what percent sugar by weight.

34%
24%
22%
18%
8.5%

I am trying to solve it using Allegation method , but not quit sure how to get the end result , Please help . Also, elaborate the steps so that I can understand the approach .
many thanks !

I started with 10% ------------ x% in the first row

16% in the second row

and x-16% and 6% in the last one

this gives me x-16/6= ? "stuck here "

The allegation formula is this:

w1/w2 = (A2 - Aavg)/(Aavg - A1)
w1/w2 is the ratio of weights of the two solutions. Here, since 1/4 of the first solution is replaced, the weight of the first solution is 3/4 and that of the second solution is 1/4 so w1/w2 = 3/1

A2 - Concentration of second solution which we have to find here
Aavg - Concentration of mixture which is 16%
A1 - Concentration of first solution which is 10%

3/1 = (A2 - 16)/(16 - 10)
A2 = 34%

To find out how you get this formula, check: http://www.veritasprep.com/blog/2011/03 ... -averages/
For more on mixtures and replacement, check:
http://www.veritasprep.com/blog/2011/04 ... -mixtures/
http://www.veritasprep.com/blog/2012/01 ... -mixtures/
Re: One-fourth of a solution that was 10% by weight was replaced   [#permalink] 18 Jan 2016, 15:02

Go to page    1   2    Next  [ 21 posts ]

Similar topics Replies Last post
Similar
Topics:
23 A certain fraction of a 15% salt solution by weight was replaced 18 15 Feb 2015, 12:02
17 10% of a 50% alcohol solution is replaced with water 11 25 Oct 2014, 21:53
7 One fourth of a solution that was 10 percent sugar by weight 7 21 Dec 2009, 05:17
18 Some part of a 50% solution of acid was replaced with an 16 12 Aug 2008, 13:27
41 A portion of the 85% solution of chemicals was replaced with 27 04 Nov 2007, 18:56
Display posts from previous: Sort by