Find all School-related info fast with the new School-Specific MBA Forum

It is currently 28 May 2016, 14:27
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

One fourth of a solution that was 10 percent sugar by weight

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
CEO
CEO
User avatar
Joined: 21 Jan 2007
Posts: 2756
Location: New York City
Followers: 9

Kudos [?]: 603 [0], given: 4

One fourth of a solution that was 10 percent sugar by weight [#permalink]

Show Tags

New post 17 Oct 2007, 13:19
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

One fourth of a solution that was 10 percent sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight ?

(A) 34%

(B) 24%

(C) 22%

(D) 18%

(E) 8.5%

How do I set this one up using the algebra?
Manager
Manager
User avatar
Joined: 25 Apr 2007
Posts: 50
Followers: 1

Kudos [?]: 2 [0], given: 0

 [#permalink]

Show Tags

New post 17 Oct 2007, 13:42
I think its A.

The way i calculated is as follows;

original solution had 10% sugar by weight ( so 100 gms contains 10 g sugar)
you replace 1/4 of it so thats 25 gms. (we can also find out that 25gms contains 2.5gms of sugar)

Now the resulting solution has 16% - 100gms contains 16gms.

75 gms = 7.5 g
100 gms = 16 g

So new solution of 25 gms has 8.5 gms of sugar which is 34% for 100 g.

Hence A.
VP
VP
User avatar
Joined: 08 Jun 2005
Posts: 1146
Followers: 6

Kudos [?]: 163 [0], given: 0

 [#permalink]

Show Tags

New post 17 Oct 2007, 15:29
see attachment.

since the old ratio is 3:1 (one fourth was replaced) and the new ratio is (x-16):6 then --->

3/1 = (x-16)/6

18 = x-16

34 = x

the answer is (A)

:)
Attachments

solution.GIF
solution.GIF [ 2.98 KiB | Viewed 683 times ]

Director
Director
User avatar
Joined: 08 Jun 2007
Posts: 583
Followers: 2

Kudos [?]: 86 [0], given: 0

Re: Mixture [#permalink]

Show Tags

New post 17 Oct 2007, 20:30
bmwhype2 wrote:
One fourth of a solution that was 10 percent sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight ?

(A) 34%

(B) 24%

(C) 22%

(D) 18%

(E) 8.5%

How do I set this one up using the algebra?


My way :

Assume 100 gm
replaced 25 gm

weight of sugar in 75 gm + weight of sugar in adding 25 gm solution = total weight in 100 gm

10/100 * 75 + x/100 * 25 = 16/100 * 100
x=34
CEO
CEO
User avatar
Joined: 29 Mar 2007
Posts: 2583
Followers: 18

Kudos [?]: 325 [0], given: 0

Re: Mixture [#permalink]

Show Tags

New post 17 Oct 2007, 22:16
bmwhype2 wrote:
One fourth of a solution that was 10 percent sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight ?

(A) 34%

(B) 24%

(C) 22%

(D) 18%

(E) 8.5%

How do I set this one up using the algebra?


Prolly more complicated than it needs to be, this one took me bout 15minutes =( I hate mixtures.

1/4x*1/10 --> 1/40x weight of sugar in the 1/4 mixture.

1/40x is replaced with something that yeilds 16/100x. 16/100x is the total weight of the sugar in x. Now to find the weight of the replacement we can take 3/40x (the amount that wasn't replaced, 3/40x is essentially 10% of 3/4x) and subtract it from the total.

16/100x -3/40x ---> 32/200x-15/200x ---> 17/200x equals weight of sugar in the new mixture.

We want weight of sugar over new mixture so 17/200x/1/4x the x's cancel and were left w/ 68/200 ---> .34

A
Re: Mixture   [#permalink] 17 Oct 2007, 22:16
Display posts from previous: Sort by

One fourth of a solution that was 10 percent sugar by weight

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.