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One hour after Yolanda started walking from X to Y, a

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One hour after Yolanda started walking from X to Y, a [#permalink] New post 22 Sep 2007, 12:13
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One hour after Yolanda started walking from X to Y, a distance of 45 miles, Bob started walking along the same road from Y to X. If Yolanda's walking rate was 3 miles per hour and Bob's was 4 miles per hour, how many miles had Bob walked when they met?

a)24
b)23
c)22
d)21
e)19.5
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Re: PS [#permalink] New post 22 Sep 2007, 13:11
inwosu wrote:
One hour after Yolanda started walking from X to Y, a distance of 45 miles, Bob started walking along the same road from Y to X. If Yolanda's walking rate was 3 miles per hour and Bob's was 4 miles per hour, how many miles had Bob walked when they met?

a)24
b)23
c)22
d)21
e)19.5


A.

In one hour, Yolanda walked: 3*1 = 3 miles
Therefore, the distance when Yolanda and Bob started at the same time is: 45-3 = 42 miles

Since they are walking toward each other, find out how long it takes for both of them to meet by adding speed:
4+3 = 7mph
Therefore, it will take them: (1/7)*42 = 6 hours to meet
In 6 hours, Bob walked: 6*4 = 24
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Re: PS [#permalink] New post 22 Sep 2007, 16:49
inwosu wrote:
One hour after Yolanda started walking from X to Y, a distance of 45 miles, Bob started walking along the same road from Y to X. If Yolanda's walking rate was 3 miles per hour and Bob's was 4 miles per hour, how many miles had Bob walked when they met?

a)24
b)23
c)22
d)21
e)19.5


since they are woking towards each other they will share total of 45 miles walk. X ------------><-----------------------Y or from x to y45

now lets make a rate equation:
Dy=Ty*Ry
Db=Tb*Rb
and we know that Ty=Tb+1

adding the distances
Db+Dy=45
Tb*4+Ty*3=45
4Tb+3(Tb+1)=45
7Tb=45-3
Tb=6

thus Db=6*4=24
A
Re: PS   [#permalink] 22 Sep 2007, 16:49
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