vanidhar wrote:
One night a certain hotel rented 3/4 of its rooms. including 2/3 of their air conditioned rooms. if 3/5 of its rooms were air conditioned, what percent of the rooms that were not rented were air conditioned?
A. 20
B. 33 1/3
C. 35
D. 40
E. 80
Here's a step-by-step approach using the
Double Matrix method.
Here, we have a population of motel rooms, and the two characteristics are:
- air conditioning or no air conditioning
- rented or not rented
So, we can set up our matrix like this:
Now since we're asked to find a certain PERCENTAGE, let's choose a nice value for the total number of motel rooms.
Notice that the question includes the fractions 3/4, 2/3 and 3/5. So, let's choose a number that works well with all of these fractions.
Since 60 is the least common denominator of 3/4, 2/3 and 3/5, let's say that there are
60 motel rooms altogether.
Now that we're set up, we can use the given information to determine the number of rooms to place in each of the four boxes.
If 3/5 of its rooms were air-conditionedSo, 3/5 of the 60 rooms are air conditioned. 3/5 of 60 = 36, which means 36 rooms have AC and the remaining 24 rooms do not have AC...
...motel rented 3/4 of its rooms3/4 of 60 = 45, so 45 rooms are rented and the remaining 15 rooms are not rented.
...a certain motel rented ....2/3 of its air-conditioned roomsSo of the 36 rooms with AC, 2/3 were rented.
Now that we know the number of rooms in 1 box, and we know the sums of the rows and columns, we can fill in the remaining boxes.
Question: what percent of the rooms that were not rented were air-conditioned?
There were 15 unrented rooms and 12 of them were air conditioned.
12/15 = 4/5 = 80%
Answer: E
This question type is
VERY COMMON on the GMAT, so be sure to master the technique.
To learn more about the Double Matrix Method, watch this video:
EXTRA PRACTICE QUESTION
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