There 64 positions for one tower to be placed. For each postion other tower can occupy (8-1) * (8-1) postions
Total = 64*49
Are you and stolyar assuming that the two towers can be arranged only in straight lines and not diagonally?
I did this way
Number of selecting two positions on a chess board = 64C2
For each of this selection, we can arrange the two towers in 2 ways.
So the total number of ways = 64C2 * 2 = 64 X 63
What am I doing wrong? Thanks