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# Out of seven models, all of different heights, five models

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Intern
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Out of seven models, all of different heights, five models [#permalink]

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16 Apr 2006, 07:00
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Out of seven models, all of different heights, five models will be chosen to pose for a photograph. If the five models are to stand in a line from shortest to tallest, and the fourth-tallest and sixth-tallest models cannot be adjacent, how many different arrangements of five models are possible?

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16 Apr 2006, 07:13
http://www.gmatclub.com/phpbb/viewtopic ... ive+models
Good explanation here!
But my 2 cents here for such kind of question If you don't have any ideas how to solve it just taka a blind but smart shot
We ha to choose 5 models out of 7
Surely you know the comb formula)) 5C7=42 In the answer choices take one that il smaller than 42.For this question we have only 2 answer choices that are smaller than 42 so your chances are 50/50.
Anyways it is better than choosing from 5
Hope this helps
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IE IMBA 2010

Intern
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Perm or Comb [#permalink]

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16 Apr 2006, 08:22
Thanks for the link. Why are we using comb formula, when the question is asking for "arrangements" which means Permutations?

According to my understanding - Selection=combination , arrangement=Permutation

Any explanations around that?
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Re: Perm or Comb [#permalink]

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16 Apr 2006, 11:30
am100 wrote:
Thanks for the link. Why are we using comb formula, when the question is asking for "arrangements" which means Permutations?

According to my understanding - Selection=combination , arrangement=Permutation

Any explanations around that?

Out of seven models, all of different heights, five models will be chosen You are right Selection=combination and thats why we are using combo formula here
_________________

IE IMBA 2010

Re: Perm or Comb   [#permalink] 16 Apr 2006, 11:30
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# Out of seven models, all of different heights, five models

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