p = 50%; 5 flips means that n = 5. The probability to find : Quant Question Archive [LOCKED]
Check GMAT Club App Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 10 Dec 2016, 14:17

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# p = 50%; 5 flips means that n = 5. The probability to find

Author Message
Senior Manager
Joined: 02 Feb 2004
Posts: 345
Followers: 1

Kudos [?]: 62 [0], given: 0

p = 50%; 5 flips means that n = 5. The probability to find [#permalink]

### Show Tags

19 Feb 2004, 03:34
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

p = 50%; 5 flips means that n = 5. The probability to find is for the coin to have heads at least 3 times.
Director
Joined: 03 Jul 2003
Posts: 652
Followers: 3

Kudos [?]: 91 [0], given: 0

### Show Tags

19 Feb 2004, 05:20
(5C3 + 5C4 + 5C5) * (1/2)^5 = 1/2
Manager
Joined: 16 Jan 2004
Posts: 64
Location: NJ
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

19 Feb 2004, 09:36
I think it should be 1/4 . May be i am wrong

p of atleast 3 heads = 1 - prob of less than 3 heads

p of 1 head = 5C1 / 32 =5/32
p of 2 heads = 5C2 /32 = 10/32

p (of atleast 3 heads ) 1-15/32 = 17/32

Please let me know where did i go wrong
SVP
Joined: 30 Oct 2003
Posts: 1793
Location: NewJersey USA
Followers: 5

Kudos [?]: 97 [0], given: 0

### Show Tags

19 Feb 2004, 09:43
Hi pakoo,

Anand.
Manager
Joined: 16 Jan 2004
Posts: 64
Location: NJ
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

19 Feb 2004, 13:28
Oops!!!

My mistake I did not count zero hands. Thanks for pointing it out
Intern
Joined: 10 Aug 2004
Posts: 40
Followers: 0

Kudos [?]: 1 [0], given: 0

### Show Tags

03 Sep 2004, 11:17
This is an old question but I want to make sure I am approaching these problems the correct way. Is the answer 1/2?[/i]
Manager
Joined: 02 Apr 2004
Posts: 224
Location: Utrecht
Followers: 1

Kudos [?]: 21 [0], given: 0

### Show Tags

03 Sep 2004, 11:23
I did the same as kpadma, only each separate.

10/32 + 5/32 + 1/32 = 16/32 = 1/2

Regards,

Alex
Display posts from previous: Sort by