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P and Q are integers. If P is divisible by 10^Q and cannot

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P and Q are integers. If P is divisible by 10^Q and cannot [#permalink] New post 27 Oct 2008, 01:19
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P and Q are integers. If P is divisible by 10^Q and cannot be divisible by 10^(Q+1), Q=?
(1) P is divisible by 2^5, but is not divisible by 2^6.
(2) P is divisible by 5^6, but is not divisible by 5^7.

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Re: DS [#permalink] New post 27 Oct 2008, 02:33
D.

10^Q = (2^Q)*(5^Q).

From stmt1: P has maximum 5 2s. Hence, P can be expressed as 2^5 * x where x does not have 2 as the factor.
Hence, 2^5 * x = (2^Q)*(5^Q) and clearly, Q will be 5. Hence, sufficient.

From stmt2: P = 5^6 * y where y does not have 5 as a factor.
Hence, 5^6 * y = (2^Q)*(5^Q) and clearly, Q will be 6. Hence, sufficient.
Re: DS   [#permalink] 27 Oct 2008, 02:33
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P and Q are integers. If P is divisible by 10^Q and cannot

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