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P can hit a target 4 times in 5 shots, Q, 3 times in 4 shots

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P can hit a target 4 times in 5 shots, Q, 3 times in 4 shots [#permalink] New post 10 Dec 2003, 06:50
P can hit a target 4 times in 5 shots, Q, 3 times in 4 shots and R, twice in 3 shots,. They fire simultaneously. What is the probability that at least 2 shots hit?
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 [#permalink] New post 10 Dec 2003, 07:03
5/6 ...i suppose..
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 [#permalink] New post 10 Dec 2003, 07:29
at least 2 means that 2 or 3

P(all 3)=4/5*3/4*2/3=2/5
P(2)=[4/5*3/4*1/3]+[3/4*2/3*1/5]+[4/5*2/3*1/4]=1/5+1/10+2/15=13/30

P=2/5+13/30=25/30=5/6
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 [#permalink] New post 10 Dec 2003, 08:41
Right.
5/6 it is...
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Probability [#permalink] New post 10 Dec 2003, 14:48
Hey guys, I'm having difficulty understand probability. Would you please explain your answer.
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Re: probability!! [#permalink] New post 13 Dec 2003, 01:27
4128851 wrote:
P can hit a target 4 times in 5 shots, Q, 3 times in 4 shots and R, twice in 3 shots,. They fire simultaneously. What is the probability that at least 2 shots hit?



prob of hitting zero shots = 1/5 * 1/4 *1/3 = 1/60

prob of hitting exactly one shot = 4/5 * 1/4*1/3 + 1/5* 3/4 * 2/3 + 1/5 * 1/4 * 2/3 = 9/60

P(0) + P(1) = 1/60 + 9/60 = 10/60 =1/6

required prob = 1- 1/6 = 5/6
Re: probability!!   [#permalink] 13 Dec 2003, 01:27
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