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# p is an integer. m=-p+(-2)^p Is m^3>1? (1) p is even (2)

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p is an integer. m=-p+(-2)^p Is m^3>1? (1) p is even (2) [#permalink]  16 Dec 2006, 07:43
p is an integer. m=-p+(-2)^p
Is m^3>1?
(1) p is even
(2) p^3<-1
Senior Manager
Joined: 23 Jun 2006
Posts: 387
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[#permalink]  16 Dec 2006, 08:02
B.

st1 is insuff: consider p=0 (then m=1) and p=2 (then m=2)
st2 is suff: if (p^3)<-1 then p<-1
then m=-p+(-2)^p. -p is at least 2 (because p is an integer less than -1) and (-2)^p is always between -1 and 1 ... so m will be at least 1 and m^3>1 as well. sufficient
[#permalink] 16 Dec 2006, 08:02
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# p is an integer. m=-p+(-2)^p Is m^3>1? (1) p is even (2)

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