p is an integer. m=-p+(-2)^p Is m^3>1? (1) p is even (2) : Quant Question Archive [LOCKED]
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 24 Jan 2017, 01:35

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# p is an integer. m=-p+(-2)^p Is m^3>1? (1) p is even (2)

Author Message
Manager
Joined: 01 Jun 2006
Posts: 140
Followers: 1

Kudos [?]: 5 [0], given: 0

p is an integer. m=-p+(-2)^p Is m^3>1? (1) p is even (2) [#permalink]

### Show Tags

16 Dec 2006, 07:43
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

p is an integer. m=-p+(-2)^p
Is m^3>1?
(1) p is even
(2) p^3<-1
Senior Manager
Joined: 23 Jun 2006
Posts: 387
Followers: 1

Kudos [?]: 322 [0], given: 0

### Show Tags

16 Dec 2006, 08:02
B.

st1 is insuff: consider p=0 (then m=1) and p=2 (then m=2)
st2 is suff: if (p^3)<-1 then p<-1
then m=-p+(-2)^p. -p is at least 2 (because p is an integer less than -1) and (-2)^p is always between -1 and 1 ... so m will be at least 1 and m^3>1 as well. sufficient
16 Dec 2006, 08:02
Display posts from previous: Sort by