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p is the probability of snow fall on any given day in the fi [#permalink]
30 Oct 2012, 06:56

2

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Difficulty:

45% (medium)

Question Stats:

51% (02:06) correct
49% (00:53) wrong based on 95 sessions

p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918.

(2) The probability that snow will fall every day during this week is .00022

Re: p is the probability of snow fall on any given day in the fi [#permalink]
30 Oct 2012, 08:15

Expert's post

p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918 --> 0.918=1-P(not snowing on ANY day)=1-(1-p)^7 --> (1-p)^7=0.082 --> we can find the single numerical value of p. Sufficient.

(2) The probability that snow will fall every day during this week is .00022 --> p^7=0.00022 --> we can find the single numerical value of p. Sufficient.

Re: p is the probability of snow fall on any given day in the fi [#permalink]
30 Oct 2012, 08:16

sanjoo wrote:

p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918.

(2) The probability that snow will fall every day during this week is .00022

Statement 1: probability of snow fall on atleast one day =0.918 => probability of no snow fall in entire week = 1-0.918 => since snow fall on one day doesnt affect probability on another day, if probability of no snow fall on a day is q, then q^7 = 1-0.918 this would give q and p =1-q Hence we can find p. Sufficient

Statement 2: probability of snow fall on every day = p^7 =0.00022 this would give p Hence sufficient.

Re: p is the probability of snow fall on any given day in the fi [#permalink]
30 Oct 2012, 08:21

Expert's post

Bunuel wrote:

p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918 --> 0.918=1-P(not snowing on ANY day)=1-(1-p)^7 --> (1-p)^7=0.082 --> we can find the single numerical value of p. Sufficient.

(2) The probability that snow will fall every day during this week is .00022 --> p^7=0.00022 --> we can find the single numerical value of p. Sufficient.

Answer: D.

Hope it's clear.

Just noticed that the two statements give two different values of p: 0.300431 and 0.300254. Thus the two statements contradict each other, which never happens on the real test. Not a good question. _________________

Re: p is the probability of snow fall on any given day in the fi [#permalink]
06 Nov 2012, 11:45

Bunuel wrote:

p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918 --> 0.918=1-P(not snowing on ANY day)=1-(1-p)^7 --> (1-p)^7=0.082 --> we can find the single numerical value of p. Sufficient.

(2) The probability that snow will fall every day during this week is .00022 --> p^7=0.00022 --> we can find the single numerical value of p. Sufficient.

Answer: D.

Hope it's clear.

not sure whether my understand is rite here.. just correct me if I am wrong..

why we represent not snowing on any day as (1-p)^7 instead of P. Is that since we are calcuating for 7 days in a week?

Re: p is the probability of snow fall on any given day in the fi [#permalink]
07 Nov 2012, 04:41

1

This post received KUDOS

Expert's post

breakit wrote:

Bunuel wrote:

p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918 --> 0.918=1-P(not snowing on ANY day)=1-(1-p)^7 --> (1-p)^7=0.082 --> we can find the single numerical value of p. Sufficient.

(2) The probability that snow will fall every day during this week is .00022 --> p^7=0.00022 --> we can find the single numerical value of p. Sufficient.

Answer: D.

Hope it's clear.

not sure whether my understand is rite here.. just correct me if I am wrong..

why we represent not snowing on any day as (1-p)^7 instead of P. Is that since we are calcuating for 7 days in a week?

The probability of snowing is p, thus the probability of not snowing is 1-p. The probability of not snowing entire week is (1-p)^7, therefore the probability of snowing on at least one day is 1-(1-p)^7.

p is the probability of snow fall on any given day [#permalink]
28 Jan 2013, 16:30

p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918.

(2) The probability that snow will fall every day during this week is .00022

I have two doubts about the wording of this question: a) When the question says "p is the probability of snow fall on any given day in the first week of December" , it means that the probability of snow fall on Monday is p, on Tuesday is p, on wednesday the same, ..., right? b) In the statement (2), I think that "this week" is not clear. Which "this week"?, the first week of december or the current week? I don't think that a real GMAT question would use "this week". What do you think?

Re: p is the probability of snow fall on any given day [#permalink]
28 Jan 2013, 16:37

Expert's post

danzig wrote:

p is the probability of snow fall on any given day in the first week of December. If snow fall on one day does not affect the probability of snow fall on any other day, what is the value of p?

(1) The probability that snow will fall on at least one day during the first week of December is .918.

(2) The probability that snow will fall every day during this week is .00022

I have two doubts about the wording of this question: a) When the question says "p is the probability of snow fall on any given day in the first week of December" , it means that the probability of snow fall on Monday is p, on Tuesday is p, on wednesday the same, ..., right? b) In the statement (2), I think that "this week" is not clear. Which "this week"?, the first week of december or the current week? I don't think that a real GMAT question would use "this week". What do you think?

Please refer to the solutions above and ask if anything remains unclear. _________________

Re: p is the probability of snow fall on any given day in the fi [#permalink]
29 Jan 2013, 14:07

Statement 1: Probability of snowing on "at least 1 day" = (1 - probability of snowing on zero days). Since there is only one unknown we can rearrange the equation to solve for p. Sufficient.

Statement 2: Since .00022 is the probability of snowing everyday, p^7 must equal 0.00022. We can backsolve to get p. Sufficient.

gmatclubot

Re: p is the probability of snow fall on any given day in the fi
[#permalink]
29 Jan 2013, 14:07

Back to hometown after a short trip to New Delhi for my visa appointment. Whoever tells you that the toughest part gets over once you get an admit is...