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Manager
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P = p1 p2 p3 is a product of three distinct primes. [#permalink]
 22 Oct 2006, 20:37
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P = p1 p2 p3 is a product of three distinct primes. Determine P:
(S1) 39 is a divisor of P
(S2) 15 is a divisor of P
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Senior Manager
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C
1) from 1 we know the number is 3* 13 but the other prime can be 2, 5, 7, 11 etc.. SO INSUFF
2) from 2 we know the number is 3 * 5 the other prime can be 2, 7, 11 etc
Combined the number has to be 3* 5* 13
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Senior Manager
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C
From 1 – insufficient
P = P1 * P2 * P3 = 39 * k (k is an integer) = 3 * 13 * k
Two prime numbers are 3, 13. we don’t know the 3rd one
From 2 – insufficient
P = P1 * P2 * P3 = 15 * m (m is an integer) = 3 * 5 * k
Consider P1 = 3 and P3 = 5
Two prime numbers are 3, 5. we don’t know the 3rd one
Together
3 prime numbers are 3, 13, 5
P = 3* 13*5
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SVP
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P = p1 p2 p3 is a product of three distinct primes. Determine P:
(S1) 39 is a divisor of P
(S2) 15 is a divisor of P
FROM ONE
P = P1*P2*P3 = 3*13*P3........NOT SUFF
FROM TWO
P =P1*P2*P3 = 3*5*P2.....NOT SUFF
BOTH TOGETHER
P = 5*3*13....SUFF
MY ANSWER IS c
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Manager
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Thank you fellas. The OA is C.
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