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P, Q, and R are nonzero integers. Is P/(Q*R) an integer? (1)

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P, Q, and R are nonzero integers. Is P/(Q*R) an integer? (1) [#permalink] New post 29 May 2003, 02:30
P, Q, and R are nonzero integers. Is P/(Q*R) an integer?

(1) P/Q=3
(2) P/R=2
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 [#permalink] New post 29 May 2003, 02:58
Try to pick numbers

P=6, Q=2, R=3
P=12, Q=4, R=6
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 [#permalink] New post 29 May 2003, 04:15
:oops:
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 [#permalink] New post 29 May 2003, 04:32
You have been so lucky with my problems for so long that I have to create something more difficult. :done
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 [#permalink] New post 29 May 2003, 04:44
yes.....really good questions.....

i am feeling a bit down now.......don't know maybe i am losing my tempo after registering for the exam. :cry: :cry: :cry:

hope to catch up in sometime :roll: :roll:
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 [#permalink] New post 21 Nov 2005, 20:18
I believe the answer to this one is E. We can write the expression P/(Q*R) as P/Q*1/R or P/R*1/Q

(1) we can substitute P/Q=3 Then the expression becomes 3*1/R. picking different values for R. if R=2, then the expression 3*1/2=3/2 a non-integer. However, if R=1 then 3*1/1=3 is an integer. therefore, (1) is insifficient.

(2)Again P/(Q*R)=P/Q*1/R. If P/Q=2 then we should pick different numbers for 2*1/R. if R=2, 2*1/2=1 which is an integer. However if R=3, 2*1/3=2/3 is not So, (2) is insufficient.

Combining statements. If pick values P=6, Q=2, R=3 6/2*3=1 integer but for values P=12, Q=4, R=6, 12/4*6=1/2 non-integer. So both statements together are insufficient. the answer is E.
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  [#permalink] 21 Nov 2005, 20:18
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P, Q, and R are nonzero integers. Is P/(Q*R) an integer? (1)

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