Last visit was: 24 Apr 2024, 04:55 It is currently 24 Apr 2024, 04:55

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
avatar
Intern
Intern
Joined: 02 Jan 2011
Posts: 7
Own Kudos [?]: 111 [19]
Given Kudos: 0
Send PM
Most Helpful Reply
Math Expert
Joined: 02 Sep 2009
Posts: 92901
Own Kudos [?]: 618710 [8]
Given Kudos: 81586
Send PM
General Discussion
avatar
Intern
Intern
Joined: 02 Jan 2011
Posts: 7
Own Kudos [?]: 111 [0]
Given Kudos: 0
Send PM
avatar
Intern
Intern
Joined: 13 Nov 2010
Posts: 31
Own Kudos [?]: 64 [3]
Given Kudos: 2
Send PM
Re: For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What [#permalink]
3
Kudos
SergeNew wrote:
For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What is the value of <3>*<2>?

(A) 60
(B) 116
(C) 210
(D) 263
(E) 478

Correct answer is 210.

I can not understand why we put 3 in the formula above 6 times and 2 only 4?

Thank you so much guys.
Serge.



The problem can be understand very simply it is stating that for any value as <x> ,x=2x+2x-1+2x-2 this process is continued till we get 2+1

so the question want us to calculate <3>*<2>

so lets substitute 3 in place of x then we get <3>=2(3)+(2*3-1)+(2*3-2)+(2*3-3)+(2*3-4)+(2*3-5) we can stop here because if we go further we will get zero and negative values to prove lets 2*3-6=6-6=0 so 0 and the numbers will be decreasing by 1 as the procedure goes , so as question states we should stop when we reach 2+1

so <3>=2(3)+(2*3-1)+(2*3-2)+(2*3-3)+(2*3-4)+(2*3-5) => <3> = 6+(6-1)+(6-2)+(6-3)+(6-4)+(6-5)=> 6+5+4+3+2+1=> 21 so for <3> we got 21 and continue the same procedure for <2>

<2>=2(2)+(2*2-1)+(2*2-2)+(2*2-3) we should stop here because we should not go beyond 1 as question states
<2>=>4+(4-1)+(4-2)+(4-3)=>4+3+2+1=10

so <3>*<2>=21*10=210 i.e c


Hope it's concise and clear.
GMAT Club Legend
GMAT Club Legend
Joined: 19 Dec 2014
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Posts: 21846
Own Kudos [?]: 11664 [0]
Given Kudos: 450
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Send PM
Re: For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What [#permalink]
Expert Reply
Hi All,

This question is an example of a "symbolism" question. You'll typically see 1 or 2 on Test Day and they almost always involve some type of simple arithmetic or algebra. The real "work" that you have to do is really about paying attention to what you're told about the symbol and how the symbol "works." You'll then be asked to perform a calculation using the symbol.

Here, we're told that for all integers X> 1, <X> = 2X + (2X-1) + (2X-2)+....+2 + 1

At first, this might look a little complicated, but symbolism questions usually DON'T involve complicated math, so we just have to figure out what this *really* means. Before I read another word of this question, I'm going to "play around" with this symbol a bit by TESTing VALUES....

Let's say X = 3....According to this symbol:

<X> = 2X + (2X-1) + (2X-2)....2 + 1
<3> = 2(3) + (6-1) + (6-2) +....+2 +1...

So....
<3> = 6 + 5 + 4 + 3 + 2 + 1 = 21

This isn't very hard at all; whatever number is inside the symbol, we just have to add it to the sum of every positive integer LESS than that number all the way down to 1.

From here, the rest of the work isn't that hard (both Bunuel and ravitejar have worked through those steps, so I won't rehash any of that here). Remember to stay calm and organized on Symbolism questions on Test Day - while relatively rare, they're usually some of the easiest points to pick up in the Quant section.

GMAT assassins aren't born, they're made,
Rich
User avatar
Senior Manager
Senior Manager
Joined: 07 Apr 2014
Status:Math is psycho-logical
Posts: 340
Own Kudos [?]: 386 [0]
Given Kudos: 169
Location: Netherlands
GMAT Date: 02-11-2015
WE:Psychology and Counseling (Other)
Re: For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What [#permalink]
I wanted to do what ravitejar did, but I made one mistake. I thought we needed to stop when the calculation gives 3, becausw 2+1=3. So, <3> gave me 18 and <2> 7, which ended in 126 (18*7).
Intern
Intern
Joined: 12 Oct 2017
Posts: 28
Own Kudos [?]: 9 [0]
Given Kudos: 16
Send PM
Re: For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What [#permalink]
<x>=2x+(2x-1)+(2x-2)+......2+1.
=> <3> = 6+5+4+3+2+1 = 21
<2> = 4+3+2+1 = 10
<3>*<2> = 210. Hence the answer is C.
Intern
Intern
Joined: 15 Aug 2018
Posts: 5
Own Kudos [?]: 2 [0]
Given Kudos: 78
Send PM
Re: For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What [#permalink]
I still didn't understand the 2+1 reference.
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 32643
Own Kudos [?]: 821 [0]
Given Kudos: 0
Send PM
Re: For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What [#permalink]
Moderators:
Math Expert
92901 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne