Company A's workforce consists of 10 percent managers and 90

Let say Company A has x employes and B has y employees. Now they merge and total no of employees = x+y employees.

Per the question Company A's workforce consists of 10 percent managers and 90 percent software engineers. Company B's workforce consists of 30 percent managers, 10 percent software engineers, and 60 percent support staff. We translate it into equation as follows:

.1x + .3y = .25 (x+y)
=> x + 3y =2.5 (x+y)
=> .5y = 1.5x
=> y=3x.
Now we know total employee = x+y. we need to find %age of x in total (x+y) ie x/(x+y) X100%
=> x/(3x+x) [substitute y=3x] => x/4x X 100%
=> .25 X 100 % => 25%.

Hence Answer C. Is it correct?

I love so solve such problem using algorithm.

Here-
-------------------M--------E-------SS
C1 --------------10 %---90%----0%
C2---------------30%----10%---60%

As, it is given that final % of managers is 25%, so we can say 10% of C1 and 30% of C2 constitute 25% of managers in merged company.
Now, let's arrange the algorithm-

---------------10--------------------------------------30
-------------------------------------25
----------------5 (=30-25)------------------------15 (=25-15) [Calculate difference diagonally; also this is the ratio of two companies]
----------------1--------------------------------------3 (Ratio remains same after dividing both 5, and 15 with 5)

This means, Company C1 has as share of \(1 / (1+3)\) \(= 1/4\)\(= 25%\)

So, the answer is C

Thanks for the solutions guys.

I had a doubt regarding the solution i have supplied under the spoiler. In that A and B are considered as the number of employees in step one and in the next step as fractions/ratios, and we get the answer that way also. Can you please explain that?

It is clear thanks, and i have used the same method while solving this question, however i had a big doubt before chosing the answer. I started to look at the other part of the provided information. Eventhough i did not used it and i think it is not of much need here, but still i thought since it is given there should be some purpose.
My question, does the GMAT sometimes use information just to distract or i am missing something?

Yes, I've seen some questions from reliable sources which had redundant information just to confuse us.

See attached grid below.

We have to find \(\frac{X}{Z}\): the number of workers that came from A over the total number of workers resulting from the merge.

Let's write the conditions for this problem:

(1) \(A + B + 25 = 100\)

(2) \(X+Y=Z\)

(3) \(A=\frac{(90X+10Y)}{Z}\)

(4) \(25=\frac{(10X+30Y)}{Z}\)

(5) \(B=\frac{60Y}{Z}\)

Very easily, we can see that using ONLY (4) and (2) we have: \(25=\frac{(10X+30Y)}{(X+Y)}\) ---> \(25X+25Y=10X+30Y\) --> \(3X=Y\)

Whit this, WE ALREADY HAVE THE SOLUTION as:

\(\frac{X}{Z}=\frac{X}{(X+Y)}=\frac{X}{(X+3X)}=\frac{X}{4X}=0.25\)

Solution: 25%

Answer: C

It's trueeeeeeeee

I'm always comfortable with these problems , even the most difficult but at 2.00 AM is not a big deal

0.1 X + 0.3 Y = 0.25 (X + Y )

Now 15 X = 5 Y ---> X / Y = 5/15 = 1/3 \(BUT\) the ration 1 : 3 is = to 4 (the total) so the parts must be 1/4 and 3/4. We care about of X so 1/4 = 25.

1. Let the total number of worforce of the resulting company be 100.
2. Let us say x number of the workforce originated from A.
3. 10 % of that number is the number of managers contributed by A which is\(x/10\).
4. (100-x) of the workforce originated from B.
5. 30 % of that number is the number of managers contributed by B which is\(3(100-x)/10\)
6. We have the total number of managers in the resulting company as 25.
7. (3) + (5) =(6) i.e.,\(x/10 + 3(100-x)/10 = 25\)
x=25.

Answer is choice C.

Use weighted avgs here. Company A has 10% managers and company B has 30% managers. Overall, the merged company has 25% managers. So what is the ratio number of employees of company A to number of employees of company B?

number of employees of company A:number of employees of company B = (30 - 25):(25 - 10) = 1:3

What percent of the workforce originated from Company A? 1/4 = 25%

Alternative approach: Apply differentials

-15A +5B = 0, 15A = 5B, A/B = 1/3
Therefore 1/4 or 25% of the managers came from division A

Hope this helps
Cheers
J

Did the same way till we get y = 3x

So, \(\frac{y}{x} =\frac{3}{1} = \frac{75}{25}\)

Contribution from x = 25%

General solution for mixture problems.

In this type of problems S1 consisting of some components and S2 consisting of one or more of the same components are mixed

Steps:

1.Identify the S1 and S2 and their components. For simplicity let us assume S1 and S2 are solutions. They may also be solids such as bars.

2.S1 and S2 are identified as follows:

(i)S1 and S2 are explicitly mentioned as two different solutions.
(ii)S1 is the original solution. S2 is the same type of solution but added to S1. The elements become added in the proportion they are present
(iii)S1 is the original solution and S2 is a different type of solution and may contain only one element ,such as water. This element will be present in S1 also.
(iv)S1 is the original solution and S2 is the same type of solution got from removing some quantity from S1. The elements are removed in the same proportion they are present.
(v)S1 is the original solution and S2 is that which is got by removing only one element from S1.
(vi)S1 and S2 are two solutions and they contain only one element or only one element is mentioned.

3.The general formula is:

re1/re2 = s1 *e1/(e1+e2) + s2* e1/(e1+e2) / s1*e2/(e1+e2) + s2* e2/(e1+e2)

where re1/re2 is the ratio of the elements in the result after s1 and s2 are mixed, s1 and s2 are the quantity of the solutions . The elements in each solution are normally given in ratios.

In this problem,

re1/re2 = 10/100 * s1 + 30/100*s2 / 90/100 *s1 + 70/100 * s2
re1/re2 = 0.1*s1 + 0.3 *s2 / 0.9*s1 + 0.7*s2
25/75= 0.1*s1 + 0.3 *s2 / 0.9*s1 + 0.7*s2
=> s1/s2 = 1/3 or s1/(s1+s2) = 1/4

The answer is therefore 25%

easy to make this question a lot harder than it needs to be (see below lol)

Total Employees:
A=100
B=100

Managers:
A (100)(.1) = 10
B (100(.3) = 30

[10(x/100)+30[(100-x)/100]]/[[100(x/100)]+[100[(100-x)/100]]] = 1/4
[(150-x)/5]/100=1/4
150-x=500/4
x=25

10%---------25%-----30%

if ratio of A/B was equal than A portion would be 50% and managers would be 20%. But result is shifted to B, so we can eliminate D and E. The true ratio is 1/3, so A=25%

C

We can let the number of people from Company A = A and the number of people from Company B = B.

Thus, 0.1A = the number of managers from Company A and 0.3B = the number of managers from Company B. When the two companies merged, because the workforce was 25% managers, we can create the following equation and determine the relationship between A and B:

0.1A + 0.3B = 0.25(A + B)

10A + 30B = 25A + 25B

5B = 15A

B = 3A

The percentage of the workforce from A is:

A/(A + B) = A/(A + 3A) = A/4A = 1/4 = 25%.

Answer: C

Assume the weightage ratio given to Company B Workforce is x.So the weightage ratio of Company A will be 1-x.
Now
(1-x)10% + x* 30% = 25 %
10-10x+30x = 25
20x = 15
x =15/20
x= 3/4

So Company A weightage ratio will be 1/4
And hence the contribution will be 25%.