P and Q are the only two applicants qualified for a short-te

I think also:

The constant here is 600 sio D = R x T (here D is some output: distance work and so on)

Q rate is 1.0 and P is 1.5 so we can set equal 1.5T = 1.0 (T + 10) ---> T = is 20 h for P so 600/20 = 30. For Q is T + 10 = 30 ---> 600/30 = 20

So P earns 30 per h Q 20 per h, the difference is 10

What do you think Bunuel ?? and is true that in most difficult problems one key could be to set equal D ( W or other output) ???

Thanks

Your approach is correct. It's basically the same as mine. You denoted P's time as T time and I denoted Q's time as T. As a result your equation is 1.5T = 1.0 (T + 10) and mine is T = 1.5 (T - 10).

Also, you are right, in similar questions equating output/distance/pay is a good strategy to attack the problem.

When it says, "a short-term research project that pays 600 dollars in total," how did you know that it was per person rather than 600 for both of them?
I was confused there and was wondering if there was a quick rule of thumb to recognize such subtle, but critical difference.

Well it's implied in the question that only one applicant can be hired for the project, so $600 that is payed for it is only for one.

Hope it's clear.

Let P & Q be the hourly wages of P & Q candidates resp.
Let "x" be the hours worked by P

scope of silly mistake: we need to find (P-Q) NOT P or Q - so be careful

Formula;
No.of hrs * hourly wage= total wage

Given;
P=1.5 Q

P's total earning;
x * 1.5Q =600------(i)
Q=600/(x * 1.5 )

Q's total earning;
(x+10) * Q =600---(ii)

Putting Q from (i) we'll get;
(x+10) * 600/(x * 1.5) =600
x=20

putting x in (i) or (ii) we'll get;
Q=20

putting Q=20 in (i) or (ii) we'll get
P=30

(P-Q)=30-20= 10

Answer : A

we know that RateP/RateQ=3/2 and TimeQ-TimeP=10

RateP/RateQ=3/2 means that TimeP/TimeQ=2/3
since we know that the difference between times of P and Q is 10, we can think that TimeP=20 TimeQ=30 or Rate P=30 RateQ=20


Rate P-RateQ=30-20=10

Answ is A

\(P = 1.5d x h = 600\)
\(Q = d x (h + 10) = dh + 10d = 600\)

\(Eq1: 1.5dh = 600\)
\(dh = 6000/15 = 400\)

Substitute dh = 400 to Eq 2:
\(400 + 10d = 600 ==> 10d = 200 ==>d=20\)
\(400 = 20h => h=20\)

P hourly rate = 600 / 20 = 30 dollars
Q hourly rate = 600 / 30 = 20 dollars

Answer: 10

Bunuel pls why did you choose T - 10 for candidate P instead of choosing T + 10 for candidate Q, i chose 2nd choice and end up solving quadratic equation that take lot of time, how to choose that strategic choice?

let Q works for x per hour, then P works for 1.5x per hour
let P works for t hours and Q works for t+10 hours
P gets 1.5tx = 600, tx = 400
also tx+ 10x = 600
10x = 200
x = 20
1.5x = 30
difference = 10

Total pay = $600
P: gets paid (1.5 per hour)(Q)
Q: 10 + P hours to get the job done
P’s hourly wage is how much greater than Q’s hourly wage?


Total Salary Rate Hours
P $600 1.5Q P
Q $600 Q P+10

Set total equal to each other.
(1.5Q)(P) = (Q)(P+10)
1.5QP = 1QP + 10Q
0.5QP = 10Q → Divide and cross out Q's to get 20 = P.

Find hourly rate.
600 = (Q)(30) → 20 = Q gets paid $20 per hour.
P gets paid 1.5 times more than Q. (20)(1.5) = $30 per hour.

$30-$20 = $10
Answer: A

Let

\(Time \ taken \ by \ P \ to \ finish \ the \ task = t\)

\(Time \ taken \ by \ Q \ to \ finish \ the \ task = t+10.\)

From the points mentioned above, we get

\(=>\frac{(salary \ paid \ to \ P)}{(Salary \ Paid \ to \ Q)} = \frac{150}{100}= \frac{3}{2} = \frac{(t+10)}{t}\)

Solving, we get t = 20

Therefore, (Salary Paid to P) - (Salary Paid to Q) = (20+10) - (20) = 10

Answer = A

We know that hourly wage = total paid/number of hours.

If we let h = the number of hours worked by P, then h + 10 = the number of hours worked by Q. Thus:

600/h = 1.5[600/(h+10)]

600/h = 900/(h + 10)

600(h + 10) = 900h

600h + 6000 = 900h

6000 = 300h

20 = h

Thus, P’s hourly wage is 600/20 = $30 and Q’s hourly wage is 600/30 = $20. Thus, P’s hourly wage is 30 - 20 = 10 dollars greater than Q’s hourly wage.

Answer: A

Hi All,

This question gives us a number of facts to work with:
1) The project pays 600 dollars in total.
2) Candidate P would be paid 50 percent more per hour than candidate Q would be paid.
3) Candidate Q would require 10 hours more than candidate P to do the job.

With this information, we can create two equations and solve using "system Algebra." We're asked for the difference between Candidate P’s hourly wage and candidate Q’s hourly wage.

X = pay per hour
T = number of hours

Candidate P = ($1.5X)(T) = 600
Candidate Q = ($X)(T+10) = 600

(1.5)(X)(T) = 600
XT + 10X = 600

In the first equation, we can divide both sides by 1.5, which gives us:
XT = 600/1.5 = 400
We can then substitute this value into the second equation:
400 + 10X = 600
10X = 200
X = 20

Since X = $20, 1.5X = $30 and the difference is $10

Final Answer:

GMAT assassins aren't born, they're made,
Rich

Let \(x\) be the # of hours required for P to do the job, then

\((x + 10)\) is the # of hours required for Q to do the same job.

Given that the hourly wage of P is 50% more than that of Q.

Hence, we have \(\frac{600}{x}\) = \(\frac{1.5*600}{(x + 10)}\)

solving we get \(x = 20\)

Hence hourly wage for P = \(600/20 = 30\)

& hourly wage for Q = \(600/30 = 20\)

Thus, P has a hourly wage greater by $10 than that of Q.

Answer A.


Thanks,
GyM

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