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Re: GMAT Diagnostic Test Question 33 [#permalink]
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KevinBrink wrote:
Dear Bunuel,

I understand the explanation, but you are adding a circle is inscribed in the MIDDLE of a semi circle. If you add MIDDLE the question clears, however this is not in the original question.

Regards

Kevin


The original question was revised.
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Re: GMAT Diagnostic Test Question 33 [#permalink]
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bb wrote:
A circle is inscribed in a half circle with a diameter of π. What is the ratio of the area of the half circle to the area not covered by the inscribed circle?

A. 1: 1
B. 1: 2
C. 1: 4
D. 3: 4
E. 2: 1


I downloaded the v6 of the diagnostic test (which I assume is the latest). The options for this question are different and 2:1 is not at all there as an option.
But answer still says that it is E.
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Re: GMAT Diagnostic Test Question 33 [#permalink]
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TirthankarP wrote:
bb wrote:
A circle is inscribed in a half circle with a diameter of π. What is the ratio of the area of the half circle to the area not covered by the inscribed circle?

A. 1: 1
B. 1: 2
C. 1: 4
D. 3: 4
E. 2: 1


I downloaded the v6 of the diagnostic test (which I assume is the latest). The options for this question are different and 2:1 is not at all there as an option.
But answer still says that it is E.


Yes it still has the error; there is no such option.

Originally posted by Anshulmodi on 20 Nov 2013, 09:37.
Last edited by Anshulmodi on 20 Nov 2013, 09:44, edited 2 times in total.
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Re: GMAT Diagnostic Test Question 33 [#permalink]
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I might have used a long method to answer the question, but here's how I solved it:-


Area of Semi-circle = Area of Entire Circle / 2

Area of Entire Circle = πr^2 --> π*(π/2)^2 --> π*(π^2/4) --> π^3/4

Area of Semi-circle = π^3/4 / 2 --> π^3/4*2 --> π^3/8


Area of Inscribed Circle = πr^2 --> π*(π/4)^2 --> π*(π^2/16) --> π^3/16

Area not covered by the Inscribed Circle
= Area of Semi-circle - Area of Inscribed Circle
= π^3/8 - π^3/16
= π^3/16


Finally :

Area of Semi-circle / Area not covered by the Inscribed Circle

= π^3/8 / π^3/16
= π^3/8 * 16/π^3
= 2:1

I have laid down each step in detail as I am new with typing math in text so tried my best not to good up :)


I hope this is also a right way to solve the problem.
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Re: GMAT Diagnostic Test Question 33 [#permalink]
Dear Bunuel,

Is the statement "A circle is inscribed right in the middle of a semicircle with a diameter of π as shown below" a little ambiguous ?

As in the first read I mis-understood that π is the diameter of the inscribed circle and not the semicircle.
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Re: GMAT Diagnostic Test Question 33 [#permalink]
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Please correct me if I'm wrong, but I did not do any calculations for this and answered it correctly in 45 seconds. As the area of the half circle is larger than the area not covered by the circle, the answer has to be a ratio which has a larger number on the left side. Answer E is the only option where the left number of the ratio is larger than the right.

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