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Re: e-GMAT Integrated Reasoning Articles [#permalink]
hey

2) Median for this data set = 82

Whereas using option 1 the value comes out to be 81.5

Since 82>81.5

So, answer for question 2 is YES.

3) A clear YES, without any calculations. The higher the weightage for fourth year, more favorable it is for the student with more marks in that year.
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
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pashraddha wrote:
hey

2) Median for this data set = 82

Whereas using option 1 the value comes out to be 81.5

Since 82>81.5

So, answer for question 2 is YES.

3) A clear YES, without any calculations. The higher the weightage for fourth year, more favorable it is for the student with more marks in that year.


Hi Prashraddha,

Q1. Median for this data set would be 81 [(80+82)/2];

Now, Median (81) < Final score, as per option 1(81.5), hence answer is NO.


Q2. Well this question certainly demands more analysis. We cannot mere consider the weight-age of option 1 & option 2 for 4th year, & jump to the conclusion.

Though weight-age of option 1 (50%) > Weight-age of option 2 (40%) for 4th year, the weight-age of option 1 (15%) < Weight-age of option 2 (20%) for 2nd year, & the weight-age of option 1 (25%) < Weight-age of option 2 (30%) for 3rd year.

For 4th year, option 1 is favorable, but for 2nd, & 3rd year, option 2 is favorable. We should also consider this aspect too.

Now, can you come up with an answer?

-Shalabh :)
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
Oops I don't know how I got median wrong :oops:

Still the answer for third question should be a YES. A student with comparatively less % in other 3 years and higher % in 4th will find Option 1 favorable.
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
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pashraddha wrote:
Oops I don't know how I got median wrong :oops:

Still the answer for third question should be a YES. A student with comparatively less % in other 3 years and higher % in 4th will find Option 1 favorable.


Hi,

Its correct, the answer to question 3 is YES only.

Just look at the analysis for more clarity.

First year score does not carry any significance, as the weight-ages for option 1 & 2 are 10% each. So no option will have an edge over the other.

Now, say the scores in II, III, & IV years are x, y, & z respectively.

Since weigh-ages for II, III year are more for option 2 over option 1, hence the 'Total gain for option 2 over option 1 for II & III' = (20-15)% of X + (30-25)% of Y = 5% of (X+Y)

Conversely, since weigh-ages for IV year is more for option 1 over option 2, hence the 'Total gain for option 1 over option 2 for IV' = (50-40)% of Z = 10% of Z

Now, we have compare 5% of (X+Y) against 10% of Z.

If 5% of (X+Y) [b]< 10% of Z[/b], then the answer is YES, else No.

So the inequality/equality is 5% of (X+Y) < = > 10% of Z ? This can be reduced to X+Y < = > 2 Z ?

Now, we know that as per the question, the student scores more marks compared to other year marks, it means Z > X, & Z > Y as well.

So it is obvious that X+Y < 2 Z. So the answer is YES.

-Shalabh
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
Hi Shalabh,
Nice question it was..Please come up with some more of these.

Ans : 1-N ,2-N, 3-Y

However, for Qs.2, can you please let me know that how the median is getting calculated as I'm not getting it as 81 but as 80.25.
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
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debayan222 wrote:
Hi Shalabh,
Nice question it was..Please come up with some more of these.

Ans : 1-N ,2-N, 3-Y

However, for Qs.2, can you please let me know that how the median is getting calculated as I'm not getting it as 81 but as 80.25.


Hi Debayan,

The median for individual numbers are calculated as the middle-most value of datatset, provided dataset is arranged in ascending order.

In Q 2, the 4 sample marks, when arranged in ascending order will look like 75, 80, 82, & 84. Here, we find that there is no middle-most term. So we take average of 2 middle-most terms i.e. 80 & 82. So the Median is (80+82)/ 2 = 81.

Median Calculation:--

Say the dataset includes 'n' values.

If n is odd, then the median of this dataset will be the value at (n + 1)/2 location when the data is arranged in ascending order.

If n is even, then the median of this dataset will be the average of two values. Value 1 at n/2 location and value 2 at n/2+1 location, when the data is arranged in ascending order.


Hope this is clear to you. :)

-Shalabh
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
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Hello friends,

What could be the answer to question 3- Students who expect to score higher marks in their 4th Year as compared to other 3 years should prefer Option 1 over Option 2? if following changes were made.



-Shalabh
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
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My quick guess will be that it has no effect. The reason is as follows:

The 2Z <=> X + Y inequality/equality that you previously generated will convert into Z <=> 0.4X + 0.6Y

Now if Z > X and Z > Y,
=> 0.4Z > 0.4X and 0.6Z > 0.6Y
=> Adding them up => Z > 0.4X + 0.6Y

So in every possible scenario, Z is always greater than 0.4X+0.6Y. (Z == 0.4X+0.6Y only when X = Y = Z)

Please let me know if am missing anything.
Thanks.
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
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abikumar wrote:
My quick guess will be that it has no effect. The reason is as follows:

The 2Z <=> X + Y inequality/equality that you previously generated will convert into Z <=> 0.4X + 0.6Y

Now if Z > X and Z > Y,
=> 0.4Z > 0.4X and 0.6Z > 0.6Y
=> Adding them up => Z > 0.4X + 0.6Y

So in every possible scenario, Z is always greater than 0.4X+0.6Y. (Z == 0.4X+0.6Y only when X = Y = Z)

Please let me know if am missing anything.
Thanks.



That's correct Abhi. You hit it right.Your concepts are clear. Did you try this one? a-question-on-multiple-graph-charts-with-varied-weights-143337.html

-Shalabh
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
egmat wrote:
debayan222 wrote:
Hi Shalabh,
Nice question it was..Please come up with some more of these.

Ans : 1-N ,2-N, 3-Y

However, for Qs.2, can you please let me know that how the median is getting calculated as I'm not getting it as 81 but as 80.25.


Hi Debayan,

The median for individual numbers are calculated as the middle-most value of datatset, provided dataset is arranged in ascending order.

In Q 2, the 4 sample marks, when arranged in ascending order will look like 75, 80, 82, & 84. Here, we find that there is no middle-most term. So we take average of 2 middle-most terms i.e. 80 & 82. So the Median is (80+82)/ 2 = 81.

Median Calculation:--

Say the dataset includes 'n' values.

If n is odd, then the median of this dataset will be the value at (n + 1)/2 location when the data is arranged in ascending order.

If n is even, then the median of this dataset will be the average of two values. Value 1 at n/2 location and value 2 at n/2+1 location, when the data is arranged in ascending order.


Hope this is clear to you. :)

-Shalabh


Hi Shalabh,
Thanks for the clarification and reminding me how to calculate median.. :) Actually I got confused with 'mean/average' and 'median' calculations.

However,a quick qs. on your explanation above :
1. You've mentioned "...when the data is arranged in ascending order."; I think order can be anything, I mean either ascending or descending. Your thoughts..?

BTW,answers will be same as mentioned above in my last post.Please confirm.
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
egmat wrote:
Hello friends,

What could be the answer to question 3- Students who expect to score higher marks in their 4th Year as compared to other 3 years should prefer Option 1 over Option 2? if following changes were made.



-Shalabh


The marginal weight-age increase in 3rd year and marginal decrease in 2nd year for option 2,don't change the fact that in Option 2, students in 4th year are still getting less marks as compared to other 3 years,whereas in option 1 it remains the same(i.e 4th year weight-age marks >3 years weight-age marks) so option 1 is still preferable for them.

Hope this makes sense.. :)
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
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The marginal weight-age increase in 3rd year and marginal decrease in 2nd year for option 2,don't change the fact that in Option 2, students in 4th year are still getting less marks as compared to other 3 years,whereas in option 1 it remains the same(i.e 4th year weight-age marks >3 years weight-age marks) so option 1 is still preferable for them.

Hope this makes sense.. :)[/quote]

Yes. You are right! By the way do not forget to attend following event this weekend to learn how to improve by up to 70 points in 25 days. Pl. click to know more.




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Re: e-GMAT Integrated Reasoning Articles [#permalink]
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debayan222 wrote:
egmat wrote:
debayan222 wrote:
Hi Shalabh,
Nice question it was..Please come up with some more of these.

Ans : 1-N ,2-N, 3-Y

However, for Qs.2, can you please let me know that how the median is getting calculated as I'm not getting it as 81 but as 80.25.


Hi Debayan,

The median for individual numbers are calculated as the middle-most value of datatset, provided dataset is arranged in ascending order.

In Q 2, the 4 sample marks, when arranged in ascending order will look like 75, 80, 82, & 84. Here, we find that there is no middle-most term. So we take average of 2 middle-most terms i.e. 80 & 82. So the Median is (80+82)/ 2 = 81.

Median Calculation:--

Say the dataset includes 'n' values.

If n is odd, then the median of this dataset will be the value at (n + 1)/2 location when the data is arranged in ascending order.

If n is even, then the median of this dataset will be the average of two values. Value 1 at n/2 location and value 2 at n/2+1 location, when the data is arranged in ascending order.


Hope this is clear to you. :)

-Shalabh


Hi Shalabh,
Thanks for the clarification and reminding me how to calculate median.. :) Actually I got confused with 'mean/average' and 'median' calculations.

However,a quick qs. on your explanation above :
1. You've mentioned "...when the data is arranged in ascending order."; I think order can be anything, I mean either ascending or descending. Your thoughts..?

BTW,answers will be same as mentioned above in my last post.Please confirm.


Hi Debayan,

Yes, you are right. Data can be arranged in ascending or descending order. However in GMAT exam, you will be able to sort in ascending order only. :)

-Shalabh Jain
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
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Hello all,

Pl. try these 3 tricky questions on weighted average- Fresh from e-GMAT bakery.
a-fresh-tricky-ta-dataset-on-weighted-average-146116.html

-Shalabh
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Re: Compare Mean and Median in less than 20 seconds [#permalink]
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OA for exercise questions-
Yes/Yes/No.
. Worth attempting questions. do give it a try. :)

-Shalabh

Originally posted by egmat on 24 Jan 2013, 03:01.
Last edited by egmat on 25 Jan 2013, 05:38, edited 1 time in total.
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
I have pdf version of og 13 but do not see the question you mention.

at what page dose that question is? pls help

pls help, dose this pdf version is not good?
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Re: e-GMAT Integrated Reasoning Articles [#permalink]
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thangvietnam wrote:
I have pdf version of og 13 but do not see the question you mention.

at what page dose that question is? pls help

pls help, dose this pdf version is not good?

Hi,

This is not given in pdf version. I have attached the question for your ready reference.

-Shalabh
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