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Re: A bottle manufacturing company has 5 machines, each of which [#permalink]
megafan wrote:
A bottle manufacturing company has 5 identical machines, each of which produces bottles at the same constant rate. How many bottles will all 5 machines produce running simultaneously for x hours?

(1) Running simultaneously, 3 of the machines produce 72,000 bottles in 2x hours?

(2) Running simultaneously, 2 of the machines produce 24,000 bottles in x hours?


St 1: 3 * 2x * Rate per machine = 72000====> Rate per machine = 12000/ x

Therefore, work done in x hrs by 5 machines = 12000/x * 5x = 60000

St2: Same process can be followed with this statement.

therefore, D
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Re: A bottle manufacturing company has 5 machines, each of which [#permalink]
megafan wrote:
A bottle manufacturing company has 5 identical machines, each of which produces bottles at the same constant rate. How many bottles will all 5 machines produce running simultaneously for x hours?

(1) Running simultaneously, 3 of the machines produce 72,000 bottles in 2x hours?

(2) Running simultaneously, 2 of the machines produce 24,000 bottles in x hours?


Let the rate of each machine be r. Thus we have to find out the value of \(5*r*x\). Thus, it is sufficient to find the value of\(r*x\).

F.S 1 states that \(3*r*2x\) = 72000. No need to calculate anything, as we know the value of\(r*x\). Sufficient.

F.S 2 states that \(2*r*x\) = 24000. Just as above, Sufficient.

D.
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Re: A bottle manufacturing company has 5 machines, each of which [#permalink]
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Re: A bottle manufacturing company has 5 machines, each of which [#permalink]
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