A and B are integers, is (0.5)^(AB) > 1?

In reply to below:

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My view:

in statement 2, when they say 2 consecutive numbers, -1 and 0 can also be 2 consecutive numbers. So this statement alone is not sufficient to answer this question.

When the 2 consecutive numbers are -1,0 -- This results in value =1.
0,1 -- This results in value <1.
1,2 -- This results in value <1
2,3 -- This results in value <1
-1,-2-- This results in value >1

So the value is not giving us definitive answers. So,

Option A is the correct answer to this.




























.

A and B are integers, is (0.5)AB>1(0.5)AB>1 ?

1. A is positive integer and B is negative integer.

2. A and B are two consecutive numbers.

So:

Statement 1) AB = a negative number. Therefore, 0.5^(any negative number) will be 1/(0.5 ^ that number) which is always greater than 1. SUFFICIENT

Statement 2) A and B are two consecutive integers. Let's try three scenarios.

Scenario 1: Consecutive numbers -1 and -2. This means 0.5 will be raised to a positive number because AB will be positive. 0.5 raised to a positive number is less than 1. Okay, this answers the question. This answer is NOT greater than 1.
Scenario 2: Consecutive numbers -1 and 0. This means 0.5 will be raised to 0, because AB will be 0. 0.5 raised to 0 is always 1. This answers the question. This answer is NOT greater than 1.
Scenario 3: Consecutive numbers 1 and 2. This means 0.5 will be raised to 2, because AB will be 2. 0.5 raised to a positive number is less than 1. This answer is NOT greater than 1.

So, Statement 2) is also Sufficient. Correct answer must be D.

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