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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
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Aww..... Guess I should have waited for this thread to arrive... :( :P
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
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vandygrad11 wrote:
Great idea. This is probably a great way to ingrain things for question writers. My Quant strength is exponents, so I'll get things started with one of those:

If \(\frac{4^{3x}}{16^{3x/2}} = (2)(2^{-3x})\), what is x?

A) x = 1/3
B) x = 2/3
C) x = 1
D) x = 3/2
E) x = 3

Here's the explanation to this question:
You should quickly realize that the bases can and should all be 2's. So, this is one methodology to solve:

\(\frac{4^{3x}}{16^{3x/2}} = (2)(2^{-3x})\)

\(\frac{(2^2)^{3x}}{(2^4)^{3x/2}} = \frac{2^1}{2^{3x}}\)

\(\frac{2^{6x}}{2^{6x}} = \frac{2^1}{2^{3x}}\)

\(2^1=2^{3x}\)

\(1=3x\)

\(\frac{1}{3}=x\)
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
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For the 2008 season, a certain sports league had eight teams. For the 2010 season, the number of teams was increased to ten. In a season, each team plays exactly two matches with each of the other teams. If the revenue per match for the 2008 season was $1 million and the revenue per match for the 2010 season was $1.25 million, what was the percentage increase in total revenues from all matches from the 2008 season to the 2010 season?

A)25%

B)50%

C)75%

D)100%

E)125%

D


Show SpoilerSolution
No. of teams in 2008 = 8
No. of matches in 2008 = \(8P_2\) = 56

Total revenue in 2008 = 56*1 million = $56 million

No. of teams in 2010 = 10
No. of matches in 2010 = \(10P_2\) = 90

Total revenue in 2008 = 90*1.25 million = $112.5 million

Percentage increase = \(\frac{112.5-56}{56}*100\) \(\approx\) 100%
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
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There is a crack at the bottom of a tank. Before the crack appeared, pipe A could fill the tank in 2 hours. Now it takes 30 min longer. How long will the crack take to empty a full tank when pipe A is closed ?

A)15 hours

B)8 hours

C)10 hours

D)12 hours

E)15 hours



Shortcut : If the pipe can fill a tank in 'a' hours but takes 'x' hours longer due to a leak, then the time taken by the leak to empty the tank fully is \(a(1+a/x)\)

Or
Before the crack appeared , Pipe A could fill \(1/2\) the tank in an hour.
Now it takes 2 hours 30 mins to fill the tank. That is \(5/2\) hours.
Hence, it fills \(2/5 th\) of the tank every hour.
The crack at the bottom accounts for this reduction in the amount . The crack therefore drains \(1/2-2/5 =5-4/10 =1/10 th\)of the tank every hour
Hence , total time taken to drain the tank is C)10 hours

Originally posted by thinktank on 02 Apr 2013, 13:28.
Last edited by thinktank on 02 Apr 2013, 15:13, edited 1 time in total.
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
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thinktank wrote:
There is a crack at the bottom of a tank. Before the crack appeared, pipe A could fill the tank in 2 hours. Now it takes 30 min longer. How long will the crack take to empty a full tank when pipe A is closed ?

A)15 hours

B)8 hours

C)10 hours

D)12 hours

E)15 hours

I'm not aware as to how to post the Answer under REVEAL here.. can someone edit this post plz ?
Solution :
Shortcut : If the pipe can fill a tank in 'a' hours but takes 'x' hours longer due to a leak, then the time taken by the leak to empty the tank fully is \(a(1+a/x)\)

Or
Before the crack appeared , Pipe A could fill \(1/2\) the tank in an hour.
Now it takes 2 hours 30 mins to fill the tank. That is \(5/2\) hours.
Hence, it fills \(2/5 th\) of the tank every hour.
The crack at the bottom accounts for this reduction in the amount . The crack therefore drains \(1/2-2/5 =5-4/10 =1/10 th\)of the tank every hour
Hence , total time taken to drain the tank is C)10 hours


Done. Mark the text you want to hide and press "Spoiler" button.
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
Here is the one from my side:

DS

If x and y are positive, is \(2x^2/17+y^2/4 < 1\)?
(1) \(2y>x^2\)

(2) \(x^2 < 9-y^2\)

1.Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
2.Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
3.BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
4.EACH statement ALONE is sufficient.
5.Statements (1) and (2) TOGETHER are NOT sufficient.


Ans. 2
This can be solved graphically.
The equation in the question stem is the equation of an ellipse with x-intercept ~ 3 and y-intercept 2 and represents the area inside the ellipse.
The statement 1 is the equation of the area enclosed inside a parabola and only some of the enclosed area will intersect with the enclosed area of ellipse. NOT SUFFICIENT.
The statement 2 is the equation of the enclosed area of a circle with radius 3 and will therefore completely enclose ellipse as x-intercept of ellipse < 3 and y-intercept of ellipse is also less than 3. SUFFICIENT.
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
vandygrad11 wrote:
vandygrad11 wrote:
Great idea. This is probably a great way to ingrain things for question writers. My Quant strength is exponents, so I'll get things started with one of those:

If \(\frac{4^{3x}}{16^{3x/2}} = (2)(2^{-3x})\), what is x?

A) x = 1/3
B) x = 2/3
C) x = 1
D) x = 3/2
E) x = 3

Here's the explanation to this question:
You should quickly realize that the bases can and should all be 2's. So, this is one methodology to solve:

\(\frac{4^{3x}}{16^{3x/2}} = (2)(2^{-3x})\)

\(\frac{(2^2)^{3x}}{(2^4)^{3x/2}} = \frac{2^1}{2^{3x}}\)

\(\frac{2^{6x}}{2^{6x}} = \frac{2^1}{2^{3x}}\)

\(2^1=2^{3x}\)

\(1=3x\)

\(\frac{1}{3}=x\)


Kudos for the question but just looking at it first time I thought of a easier way. Correct me if i am wrong

\(\frac{4^{3x}}{16^{3x/2}} = (2)(2^{-3x})\)
\(\frac{(4)^{3x}}{(4)^{2*3x/2}} = 2^{1-3x}\)
Numerator and denominator are equal after cancelling out the 2
\(1 = 2^{1-3x}\)

\(2^0 = 2^{1-3x}\)

\(1-3x = 0\)

\(\frac{1}{3}=x\)
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
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Highest prime factor of (\(97^3\) -\(57^3\) - \(40^3\)) is

1) 97
2) 19
3) 17
4) 5
5) 3

Answer : Option 1.

Explanation :
We know, \(a^3\) +\(b^3\) + \(c^3\) = 3abc if a+b+c = 0.
Here a+b+c = 97 - 57 - 40 = 0.
So, The given expression can be simplified to = 3 * 97 * 57 * 40.
So,the highest prime factor would be 97.

Originally posted by subhendu009 on 04 Apr 2013, 05:51.
Last edited by subhendu009 on 04 Apr 2013, 05:56, edited 1 time in total.
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
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Guys please provide solutions to your questions under the spoilers.
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
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A and B together can do a work in 20 days. B and C together can finish it in 25 days. If A does double the work in a day than C, then the number of days in which C alone can finish it is?

A) 70 days
B) 80 days
C) 85 days
D) 100 days
E) 120 days

Regards,

Naren


Answer = D

Solution :-
Let the work be 100%
A and B together can do a work in 20 days. that mean in a day they are doing 100/20 = 5 % of work
B and C together can finish it in 25 days. that means in a day they are doing 100/25 = 4% of work
B + A = 5
B + C = 4
A does double the work in a day than C. So A = 2C
B + 2C = 5
B + C = 4
Upon Solving we get C = 1 that mean C does 1% of the work in a day, Hence to complete the whole work it would take him 100 days.

Originally posted by Narenn on 04 Apr 2013, 07:05.
Last edited by Narenn on 07 Apr 2013, 09:53, edited 1 time in total.
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
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By what percentage must a trader mark his goods up if he has to make a profit of \(20%\) after providing a discount of \(25%\) on his marked price ?

A)25%

B)30%

C)50%

D)60%

E)70%

D
A handy shortcut :
When ever a trader marks his goods up by \(x%\) and offers a discount of \(y%\) then the profit/loss percentage he makes is given by
\(x-y-(xy/100)\)

+1 if u think this approach would help you save precious time :)
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
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Here is one more : this time on Permutations and Combinations

Five persons entered the lift cabin on the ground floor of an 8 floor house. Suppose each of them can leave the cabin independently at any floor beginning with the first. Find the total number of ways in which each of the five persons can leave the cabin
i) At any one of the 7 floors
ii) At different floors.

A) i) 7^5 ii) 7!
B) i) 35 ii) 7!
C) i) 5^7 ii) 7!
D) i) 5^7 ii) 2520
E) i) 7^5 ii) 2520


Correct Choice is E
Let the five persons be b,c,d,e,f
I) b can leave the cabin at any one of the seven floors. So he has 7 options
Similarly each of c,d,e,f also has 7 options. Thus the total number of ways in which each of the five persons can leave the cabin at any of the seven floors is 7 X 7 X 7 X 7 X7 = 7^5
II) b can leave the cabin in 7 ways. c can leave the cabin in 6 ways, since he can not leave at where b left. In the same way d has 5, e has 4, and f has 3 way.
Hence total number of ways = 7 X 6 X 5 X 4 X 3 = 2520
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
(1/-2)^-3 * 64^(-1/2)

a) (-1/64)
b) 1
c) (1/64)
d) (-1)
e) (-64)



= (-2)^3 * (1/64)^1/2

= -8 * (1/8) = -1

Originally posted by shivanigs on 13 Apr 2013, 03:31.
Last edited by shivanigs on 13 Apr 2013, 04:08, edited 3 times in total.
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
/x-3/ + /x-2/ = 0. What is the value of x?


Modulus hence 2 scenarios,positive and negative:

1. x - 3 + x - 2 = 0 2. -x + 3 - x +2 = 0

2x - 5 = 0 -2x +5 = 0

2x = 5 -2x = -5

x = 5/2 x = 5/2
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
A and B can complete building a house together in 30 days. If A can build the house alone in 90 days, how long will it take for B to build a house by himself?

a) 45 days

b) 60 days

c) 15 days

d) 30 days

e) -60 days



Let x be the number of days it takes B to build a house.

So,(1/90) + (1/x) = (1/30)

(1/x) = (1/30) - (1/90)

(1/x) = (3 - 1)/90

(1/x) = 2/90

(1/x) = (1/45) - B does (1/45) th of the work in 1 hour.

So amount of time of time it takes him to build 1 whole house,

Rate * Time = Work

1/45 * Time = 1

Time = 45 days
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Lucky owned a car worth $40,000.Happy bought the car from Lucky for $ 55,000.Happy then sold it to Smiley for $50,000. Lucky started to miss his car and bought it back from Smiley for $45,000. What is Lucky's net profit/loss %?


Note : The answer choices are in the mixed fraction format


a) 18(2/11)% profit

b) 37(1/2)% profit

c) 12(2/4)% loss

d) 9(1/11)% loss

e) 25% profit


Lucky's original cost for the car = $ 40,000

Happy paid him $ 55,000,so Lucky's profit amount = $ 15,000

Lucky then paid Smiley $ 45,000, hence Lucky's net profit now = $ 10,000

Therefore Lucky's profit % = (10,000/40,000) * 100 = 25%
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Re: Submit Your Own GMAT Math Questions - Get GMAT Club Tests [#permalink]
Here is my question about Patterns/Series

Given \(a_1=-81\) and \(a_n=a_{n-1}+3\) for \(n>1\), what is the value of the sum of the first 54 elements: \(a_1+a_2+...+a_{53}+a_{54}\) ?

A)0
B)-78
C)-81
D)81
E)78

OA: C)-81

the sequence is as follow:
\(a_1=-81\) \(a_2=-78\) ... and this will reach 0 is 27 passages \(a_{28}=0\) and then will become positive and every term will balance its negative correspondent.

\(a_{27}=-3\) will be balanced by \(a_{29}=3\) => sum=0 and so on...
This process continues for all terms, if the question were "What is the sum of the first 55 terms the balance will be perfect and the sum would be 0.

But here we are asked the sum of the 54 terms: the very first term will not be balanced!
\(a_{1}=-81\), \(a_{2}=-78\), ..., \(a_{54}=78\)

The sum is -81.
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