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Re: Half an hour after Car A started traveling from Newtown to Oldtown, a [#permalink]
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In questions where you have the speeds given in miles/hour, its convenient to convert the time from minutes to hours.
The one who started half an hour (or 30 mins.) earlier must have traveled for 30+15=45 mins when he meets the other person driving from oldtown.
Now it is always easy for problems like these(where you have figures like 15 mins. or 45 mins) to convert time expressed in mins to hours.
45 mins=3/4 of an hr
15 mins=1/4 of an hr.
Now, distance traveled by the one who started earlier when he meets the other on his way=\(\frac{3.(x+8)}{4}\) miles
where x-speed of the person( in miles/hr) who started later.
When the meeting happens, the one who started late would have traveled \(\frac{x}{4}\) miles
Hence, \(\frac{3.(x+8)}{4} + \frac{x}{4}=62\)
Solving, we get x=56.
Therefore, the answer would be \(\frac{x}{4}=\frac{56}{4}=14\)
I hope this answers your question. :)
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Re: Half an hour after Car A started traveling from Newtown to Oldtown, a [#permalink]
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Here's how I did this one

\((2B+8)(1/4) = (62- ((B+8)/2)\)

Solving we get \(B=56\)

Therefore, \(56/4= 14\)

Answer: A
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Re: Half an hour after Car A started traveling from Newtown to Oldtown, a [#permalink]
Half an hour after car A started traveling from Newtown to Oldtown, a distance of 62 miles, car B started traveling along the same road from Oldtown to Newtown. The cars each met each other on the road 15 minutes after car B started it's trip. If Car A traveled at a constant rate that was 8 MPH greater than car B's constant rate, how many miles had car B driven when they met?

let b/4=B's miles
b/4=62-(b+8)(3/4)
b/4=14 miles
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Re: Half an hour after Car A started traveling from Newtown to Oldtown, a [#permalink]
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My way of solving by substitution


speed of car B (Y) = x/0.25
speed of car A(Y+8) = 62-x/0.75

x/0.25 + 8 = 62-x/0.75

x=14 miles

Hope its clear!!
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Re: Half an hour after Car A started traveling from Newtown to Oldtown, a [#permalink]
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WholeLottaLove wrote:
Half an hour after Car A started traveling from Newtown to Oldtown, a distance of 62 miles, Car B started traveling along the same road from Oldtown to Newtown. The cars met each other on the road 15 minutes after Car B started it's trip. If Car A traveled at a constant rate that was 8 miles per hour greater than Car B's constant rate, how many miles had Car B driven when they met?


A. 14 miles

B. 12 miles

C. 10 miles

D. 9 miles

E. 8 miles


Thanks![/spoiler]


Let’s let the rate of Car B be v. Then, the rate of Car A is v + 8.

Since Car A had been traveling for 30 minutes when Car B started its trip and since the two cars met 15 minutes after, the total travel time for Car A is 30 + 15 = 45 minutes = 3/4 hour, and the total travel time for Car B is 15 minutes = 1/4 hour. Since the sum of the distances traveled by the two cars must equal the total distance between the two towns, which is 62, we can create the following equation:

(v + 8)(3/4) + v(1/4) = 62

Let’s multiply each side of this equation by 4:

(v + 8)(3) + v = 248

3v + 24 + v = 248

4v = 224

v = 56

Since the rate of Car B is v = 56 mph and since Car B traveled for 1/4 hour when the two cars met, Car B traveled 56 * 1/4 = 14 miles.

Answer: A
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Re: Half an hour after Car A started traveling from Newtown to Oldtown, a [#permalink]
Why do we know we can add these two rate*times of the two cars together to get 62? The problem does not say that if we were to add both, they would reach the end of the road so how is this assumed?
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Re: Half an hour after Car A started traveling from Newtown to Oldtown, a [#permalink]
AcceptMePLZ wrote:
Why do we know we can add these two rate*times of the two cars together to get 62? The problem does not say that if we were to add both, they would reach the end of the road so how is this assumed?


From question we know that both cars started from the opposite ends and before meeting Car A had traveled for 45 mins and Car B had traveled for 15 min.
So the total Distance 62 miles will be equal to the sum of their distances traveled.
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Re: Half an hour after Car A started traveling from Newtown to Oldtown, a [#permalink]
took me a while to figure out. But the main trick here is to:

add both the distances together

(8 +x) * 3/4 + x/4 = 62

x = 56

Distance covered by B is 56/4 which is 14.

A
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Re: Half an hour after Car A started traveling from Newtown to Oldtown, a [#permalink]
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