ps combinatorics

I am wrong for the second question:
Total outcome should be 5!/2! because there are 2 G's which can be interchanged. --> 60
4! would be all unfavorable outcomes as previously explained
Answer should be: 60 - 24 = 36

I would like to underline one point and gather your comments guys :

About the 2nd question, the 96 answer considers that all words are 5 letters long and the two G are distinct.
When I first tried to answer I was thinking about 5 ar less characters words...

thanks guys

36 is the caorrect answer for the second problem

6 ppl need to divide into 3 groups of 2

is it 6c2 * 4c2 * 2c2*??

Hah ! Let me try something Ian taught me yesterday and see if I get this right !

6C2*4C2*2C2/3! = 15*6*1/6 = 15 ways
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another one... 5 letter word

DEFGG

how mnay words can you make where the two G's are not together!

Do the words have to be real words ? Or just any combination of letters as long as the two Gs are not together.

If the words have to be real:
Then the number of words = 0 (The only word that can be made is egg, and it's out because the two g's are together)

If it's any letters and the words do not need to make sense:
Then , we can either has 1 letter word, 2 letter words, 3 letter words, 4 letter words, can't be 5 as that will give 2 g's
So 1 letter word - 5
2 letter words - 4P2 (remove 1 G) = 12 (use permutation assuming we can swtich the letters around and form another word)
3 letter words - 4P3 = 24
4 letter words - 4P4 = 16

So total - 4 + 12 + 24 + 16 = 56

ywilfred, I believe that you have to use all the letters to form a 5 letter word. Also, why did you omit to account for 5 letter words in your calculation? Although there are 2 G's, you should still account for words that can be formed when the 2 G's are apart.

The answer to the first problem according to my working is
6C2*4C2*2C2/3!
=15*6/6=15

In the word problem, the number of different words possible is 5!/2! ( as G is coming twice)
=60

If G and G is treated as one unit, number of ways that the rest of the letters can be arranged= 4!=24

The number of ways in which the two Gs will be apart
=60-24
=36