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Six machines each working at the same

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ritula
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Six machines each working at the same [#permalink] New post   13 Nov 2008, 03:46
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Re: Six machines each working at the same [#permalink] New post   13 Nov 2008, 07:29
more workers, lesser days....(inverse ratio since rates are same..)
6/x=8/12==> x=9

so 9-6 =3 additional workers reqd.
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Re: Six machines each working at the same [#permalink] New post   13 Nov 2008, 12:19
using unitary method
six m/cs------12 days
one m/cs------72 days
nine m/cs------8 days
=> additional machines= 9-6=3
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Re: Six machines each working at the same [#permalink] New post   13 Nov 2008, 20:07
6 machines * Rate of individual machine (R) * 12 days = 1 work

Therefore R = 1/72

Let X be the total number of machines reqd to complete work in 8 days

we have,

X * 1/72 * 8 = 1

X =9

we need to know how many "additional" machines are reqd = 9 -6 = 3
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Re: Six machines each working at the same [#permalink] New post   13 Nov 2008, 21:30
Ohhhhhhhhhhhh. I didnt notice the word "additional" in the question and got 6 as the final answer. :x
This shows we shld read wht exactly is required in the question
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Re: Six machines each working at the same [#permalink] New post   13 Nov 2008, 21:47
ritula wrote:
Ohhhhhhhhhhhh. I didnt notice the word "additional" in the question and got 6 as the final answer. :x
This shows we shld read wht exactly is required in the question


But then you should get 9 as answer right :)
or was it an upside down problem (9 6) :wink: :-D



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Re: Six machines each working at the same [#permalink]
13 Nov 2008, 21:47
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