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Re: The integers r and s are distinct, r ≠ 0, and s ≠ 0. If r^2s^2 = -rs, [#permalink]
rs(rs+1)=0
rs = -1
either r or s can be -1 so B,C , E eliminated

say r = -1 and s= 1 or r=1 or s= -1
r-s can never be 0 since opposite signs.
option D eliminated

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Re: The integers r and s are distinct, r ≠ 0, and s ≠ 0. If r^2s^2 = -rs, [#permalink]
Hi all,

How can rs=-1 if they're both squared? Doesn't anything squared yield a positive number?
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Re: The integers r and s are distinct, r ≠ 0, and s ≠ 0. If r^2s^2 = -rs, [#permalink]
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Clycos wrote:
Hi all,

How can rs=-1 if they're both squared? Doesn't anything squared yield a positive number?


\(rs = -1\) means that \(-rs = -(-1) = 1\), so \(r^2s^2 = -rs = 1 = positive\).
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Re: The integers r and s are distinct, r 0, and s 0. If r^2s^2 = -rs, [#permalink]
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Re: The integers r and s are distinct, r 0, and s 0. If r^2s^2 = -rs, [#permalink]
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