Bunuel wrote:
amirdubai1982 wrote:
Question: If x, y, and z are integers greater than 0 and x = y + z, what is the value of ?
(1) (x-y)/y=4/5
(2) z/y=4/5
Question should be:
If x, y, and z are integers greater than 0 and x=y+z, what is the value of (y-z)/y?\(\frac{y-z}{y}=1-\frac{z}{y}=?\) So, basically the question asks about the value of \(\frac{z}{y}\).
(1) \(\frac{x-y}{y}=\frac{4}{5}\) --> cross multiply --> \(5x-5y=4y\) --> \(5x=9y\) --> as \(x=y+z\) (or as \(5x=5y+5z\)) then \(9y=5y+5z\) --> \(4y=5z\) --> \(\frac{z}{y}=\frac{4}{5}\). Sufficient.
(2) \(\frac{z}{y}=\frac{4}{5}\), directly gives the value of the ratio we need. Sufficient.
Answer: D.
Do we always have to reduce ratio's to their lowest forms?
What I did was this, please tell me why this reasoning is wrong.
we need to find the value of \(\frac{y-z}{y}\) or \(1- \frac{y}{z}\) so we need to find the value of
\(\frac{y}{z}\)
(1)\(\frac{x-y}{y} = \frac{4}{5}\)
\(\frac{x}{y} -1 = \frac{4}{5}\) ,\(\frac{x}{y} = \frac{4}{5} + 1\), \(\frac{x}{y}= \frac{9}{5}\)
now given x= y+z so if \(\frac{x}{y} = \frac{9}{5}\) then we can take x= 9 and y=5 then z=4 here \(\frac{z}{y} =\frac{4}{5}\)
but if \(\frac{x}{y} = \frac{9}{5}\)then we can also take x= 18 and z=10 can't we? then z= 8 here \(\frac{z}{y} =\frac{8}{10}\)
So I thought statement 1 did not give us the actual values of x and y, so I thought there were many possibilities hence marked statement as insufficient.
so this was my confusion , I though since we got a ratio at the end of simplification of 1 we do not know the actual values of x and y , since we got \(\frac{x}{y} = \frac{9}{5}\), \(\frac{x}{y}\) could also be \(\frac{18}{10}\),or \(\frac{27}{15}\), if x and y differs so will z and hence will \(\frac{z}{y}\) unless we are always reducing ratios to their lowest form
please tell me how can we be sure of x and y from this ratio
thanks