Last visit was: 24 Apr 2024, 11:51 It is currently 24 Apr 2024, 11:51

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
User avatar
Manager
Manager
Joined: 25 Jul 2010
Posts: 75
Own Kudos [?]: 3176 [116]
Given Kudos: 29
Send PM
Most Helpful Reply
Math Expert
Joined: 02 Sep 2009
Posts: 92902
Own Kudos [?]: 618791 [57]
Given Kudos: 81588
Send PM
User avatar
Senior Manager
Senior Manager
Joined: 03 Feb 2011
Status:Impossible is not a fact. It's an opinion. It's a dare. Impossible is nothing.
Affiliations: University of Chicago Booth School of Business
Posts: 472
Own Kudos [?]: 892 [14]
Given Kudos: 123
Send PM
General Discussion
User avatar
Manager
Manager
Joined: 01 Oct 2010
Posts: 61
Own Kudos [?]: 117 [2]
Given Kudos: 19
 Q49  V35
Send PM
Re: Largest possible range in Set R [#permalink]
2
Kudos
I took the set to be m, m, 55, 55, 3m+20. (second value has to be minimum possible - m, and fourth value has to be minimum possible - 55).

now average is 55 so 55 = (6m + 130)/5 which gives m = 29, and 3m+20=107

so range is largest - smallest = 107-29 = 78
Retired Moderator
Joined: 16 Nov 2010
Posts: 909
Own Kudos [?]: 1172 [3]
Given Kudos: 43
Location: United States (IN)
Concentration: Strategy, Technology
Send PM
Re: Largest possible range in Set R [#permalink]
2
Kudos
1
Bookmarks
Let smallest # = x, Largest = 3x + 20

So range = 2x + 20

x, x, 55, 55, 3x+20, For Max range lowest should be as low as possible and highest should be as high as possible

also, the 2nd value has to be minimized, so it is x, the fourth value also ahs to be kept at minimum, so it is 55

3x + 20 + 110 + 2x = 275

=> 5x = 275 - 130 = 145 => x = 29 , so range = 29*2 + 20 = 78

So answer is A.
User avatar
Manager
Manager
Joined: 03 Aug 2010
Posts: 68
Own Kudos [?]: 302 [1]
Given Kudos: 63
GMAT Date: 08-08-2011
Send PM
Re: Largest possible range in Set R [#permalink]
1
Kudos
gmat1220 wrote:
Backsolving : Range = 2a + 20 where a = first number.

Hence the answer is even and highest options. It should be A.


That's an awesome application of number properties to solve this question is seconds.
Kudos
Math Expert
Joined: 02 Sep 2009
Posts: 92902
Own Kudos [?]: 618791 [3]
Given Kudos: 81588
Send PM
Set R contains five numbers that have an average value of 55 [#permalink]
3
Kudos
Expert Reply
Yalephd wrote:
gmat1220 wrote:
Backsolving : Range = 2a + 20 where a = first number.

Hence the answer is even and highest options. It should be A.


That's an awesome application of number properties to solve this question is seconds.
Kudos


That's not correct. Yes, the range equals to 2a+20 but without any further calculation we cannot say whether it must be even, for example if a is not an integer then 2a+20 can be odd or not an integer at all. Also the answer is not necessarily the highest option, it just happened to be so in this particular case.
User avatar
Manager
Manager
Joined: 03 Aug 2010
Posts: 68
Own Kudos [?]: 302 [0]
Given Kudos: 63
GMAT Date: 08-08-2011
Send PM
Re: Largest possible range in Set R [#permalink]
Bunuel wrote:
Yalephd wrote:
gmat1220 wrote:
Backsolving : Range = 2a + 20 where a = first number.

Hence the answer is even and highest options. It should be A.


That's an awesome application of number properties to solve this question is seconds.
Kudos


That's not correct. Yes, the range equals to 2a+20 but without any further calculation we can not say whether it must be even, for example if a is not an integer then 2a+20 can be odd or not an integer at all. Also the answer is not necessarily the highest option, it just happened to be so in this particular case.


Thanks. Assuming that A is an integer is where I erred.
User avatar
Senior Manager
Senior Manager
Joined: 03 Feb 2011
Status:Impossible is not a fact. It's an opinion. It's a dare. Impossible is nothing.
Affiliations: University of Chicago Booth School of Business
Posts: 472
Own Kudos [?]: 892 [0]
Given Kudos: 123
Send PM
Re: Largest possible range in Set R [#permalink]
I was back solving - to confirm the answer.

x^2 = 4
Implies x is not necessarily 2. It can be -2 :-D
User avatar
Director
Director
Joined: 08 May 2009
Status:There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Posts: 552
Own Kudos [?]: 589 [1]
Given Kudos: 10
Send PM
Re: Largest possible range in Set R [#permalink]
1
Kudos
max range will be when 55*3 = 165 will give 110 as range.But the value isn't present.
Hence go for two small numbers , 55*2 and largest number combination.
thus 2x+110 + 3x+20 = 275
will give, x= 29 and 3x+20 = 97.
Range = 78.
User avatar
Director
Director
Joined: 08 May 2009
Status:There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Posts: 552
Own Kudos [?]: 589 [0]
Given Kudos: 10
Send PM
Re: Largest possible range in Set R [#permalink]
max range will be when 55*3 = 165 will give 110 as range.But the value isn't present.
Hence go for two small numbers , 55*2 and largest number combination.
thus 2x+110 + 3x+20 = 275
will give, x= 29 and 3x+20 = 97.
Range = 78.
User avatar
Manager
Manager
Joined: 25 May 2011
Posts: 60
Own Kudos [?]: 148 [1]
Given Kudos: 71
Send PM
Re: Largest possible range in Set R [#permalink]
1
Kudos
Bunuel wrote:
Orange08 wrote:
Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?


78
77 1/5
66 1/7
55 1/7
52


{\(a_1\), \(a_2\), \(a_3\), \(a_4\), \(a_5\)}
As mean of 5 numbers is 55 then the sum of these numbers is \(5*55=275\);
The median of the set is equal to the mean --> \(mean=median=a_3=55\);
The largest number in the set is equal to 20 more than three times the smallest number --> \(a_5=3a_1+20\).

So our set is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(a_1+a_2+55+a_4+3a_1+20=275\).

The range of a set is the difference between the largest and smallest elements of a set.

\(Range=a_5-a_1=3a_1+20-a_1=2a_1+20\) --> so to maximize the range we should maximize the value of \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\).

Min possible value of \(a_2\) is \(a_1\) and min possible value of \(a_4\) is \(median=a_3=55\) --> set becomes: {\(a_1\), \(a_1\), \(55\), \(55\), \(3a_1+20\)} --> \(a_1+a_1+55+55+3a_1+20=275\) --> \(a_1=29\) --> \(Range=2a_1+20=78\)

Answer: A.


my approach was like yours, but it took me 6 min!!! :( :cry:
User avatar
Senior Manager
Senior Manager
Joined: 06 Aug 2011
Posts: 269
Own Kudos [?]: 596 [0]
Given Kudos: 82
Send PM
Re: Largest possible range in Set R [#permalink]
Bunuel wrote:
Orange08 wrote:
Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?


78
77 1/5
66 1/7
55 1/7
52


{\(a_1\), \(a_2\), \(a_3\), \(a_4\), \(a_5\)}
As mean of 5 numbers is 55 then the sum of these numbers is \(5*55=275\);
The median of the set is equal to the mean --> \(mean=median=a_3=55\);
The largest number in the set is equal to 20 more than three times the smallest number --> \(a_5=3a_1+20\).

So our set is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(a_1+a_2+55+a_4+3a_1+20=275\).

The range of a set is the difference between the largest and smallest elements of a set.

\(Range=a_5-a_1=3a_1+20-a_1=2a_1+20\) --> so to maximize the range we should maximize the value of \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\).

Min possible value of \(a_2\) is \(a_1\) and min possible value of \(a_4\) is \(median=a_3=55\) --> set becomes: {\(a_1\), \(a_1\), \(55\), \(55\), \(3a_1+20\)} --> \(a_1+a_1+55+55+3a_1+20=275\) --> \(a_1=29\) --> \(Range=2a_1+20=78\)

Answer: A.


Bunuel sir..

few questions that cums in my mnd like ..y did bunuel take A1 is equal to A2..and y didnt he take a2=55 instead of A4=55?

i got lots of questions like this and i cant give ans correctly..

Thank u in advance bunuel..
Math Expert
Joined: 02 Sep 2009
Posts: 92902
Own Kudos [?]: 618791 [5]
Given Kudos: 81588
Send PM
Re: Largest possible range in Set R [#permalink]
2
Kudos
3
Bookmarks
Expert Reply
sanjoo wrote:
Bunuel wrote:
Orange08 wrote:
Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?


78
77 1/5
66 1/7
55 1/7
52


{\(a_1\), \(a_2\), \(a_3\), \(a_4\), \(a_5\)}
As mean of 5 numbers is 55 then the sum of these numbers is \(5*55=275\);
The median of the set is equal to the mean --> \(mean=median=a_3=55\);
The largest number in the set is equal to 20 more than three times the smallest number --> \(a_5=3a_1+20\).

So our set is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(a_1+a_2+55+a_4+3a_1+20=275\).

The range of a set is the difference between the largest and smallest elements of a set.

\(Range=a_5-a_1=3a_1+20-a_1=2a_1+20\) --> so to maximize the range we should maximize the value of \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\).

Min possible value of \(a_2\) is \(a_1\) and min possible value of \(a_4\) is \(median=a_3=55\) --> set becomes: {\(a_1\), \(a_1\), \(55\), \(55\), \(3a_1+20\)} --> \(a_1+a_1+55+55+3a_1+20=275\) --> \(a_1=29\) --> \(Range=2a_1+20=78\)

Answer: A.


Bunuel sir..

few questions that cums in my mnd like ..y did bunuel take A1 is equal to A2..and y didnt he take a2=55 instead of A4=55?

i got lots of questions like this and i cant give ans correctly..

Thank u in advance bunuel..


After some steps we have that our set in ascending order is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(Range=2a_1+20\).

We need to maximize \(Range=2a_1+20\), thus we need to maximize \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\) (remember the sum of the terms is fixed, so we cannot just make \(a_1\) as large as we want).

Now, since the set is in ascending order min possible value of \(a_2\) is \(a_1\) (it cannot be less than the first term) and min possible value of \(a_4\) is \(median=a_3=55\) (it cannot be less than the third term).

Similar questions to practice:
if-the-average-of-5-positive-integers-is-40-and-the-127038.html
the-average-arithmetic-mean-of-the-5-positive-integers-k-107059.html
a-certain-city-with-population-of-132-000-is-to-be-divided-76217.html
five-peices-of-wood-have-an-average-length-of-124-inches-and-123513.html
three-boxes-of-supplies-have-an-average-arithmetic-mean-105819.html
a-set-of-25-different-integers-has-a-median-of-50-and-a-129345.html
three-people-each-took-5-tests-if-the-ranges-of-their-score-127935.html
each-senior-in-a-college-course-wrote-a-thesis-the-lengths-126964.html
in-a-certain-set-of-five-numbers-the-median-is-128514.html
shaggy-has-to-learn-the-same-71-hiragana-characters-and-126948.html

Other min/max questions:
PS: search.php?search_id=tag&tag_id=63
DS: search.php?search_id=tag&tag_id=42

Hope it helps.
User avatar
Senior Manager
Senior Manager
Joined: 06 Aug 2011
Posts: 269
Own Kudos [?]: 596 [1]
Given Kudos: 82
Send PM
Re: Set R contains five numbers that have an average value of 55 [#permalink]
1
Kudos
Thanks alot Bunuel..now i got that :)..

i think in REAL GMAT these type of question cum frequenlty..!!.
User avatar
Senior Manager
Senior Manager
Joined: 22 Jul 2012
Status:Gonna rock this time!!!
Posts: 356
Own Kudos [?]: 166 [0]
Given Kudos: 562
Location: India
GMAT 1: 640 Q43 V34
GMAT 2: 630 Q47 V29
WE:Information Technology (Computer Software)
Send PM
Re: Set R contains five numbers that have an average value of 55 [#permalink]
Hi ,

Here's how I did..

smallest no: s
largest no: 3s+20

since mean = median,

thought that numbers are in AP.

so average= (last no+first no)/2

therefore 55=(s+3s+20)/2
=> s=22.5


now l=20+3s
=> l=87.25

range =l-s=65..
Please let me know where I am going wrong.
User avatar
Senior Manager
Senior Manager
Joined: 27 Jun 2012
Posts: 325
Own Kudos [?]: 2467 [1]
Given Kudos: 185
Concentration: Strategy, Finance
Send PM
Re: Set R contains five numbers that have an average value of 55 [#permalink]
1
Kudos
Sachin9 wrote:
Hi ,

Here's how I did..

smallest no: s
largest no: 3s+20

since mean = median,

thought that numbers are in AP.

so average= (last no+first no)/2


therefore 55=(s+3s+20)/2
=> s=22.5


now l=20+3s
=> l=87.25

range =l-s=65..
Please let me know where I am going wrong.


Sachin, you assumed that the numbers are in AP, but problem doesn't state that.
This set S = {29, 29, 55, 55, 107} has the maximum range i.e. 78 and mean/median 55.

Note that these numbers are not in AP/sequence. Hence you cannot take average of last & first to find the mean.
User avatar
Senior Manager
Senior Manager
Joined: 22 Jul 2012
Status:Gonna rock this time!!!
Posts: 356
Own Kudos [?]: 166 [0]
Given Kudos: 562
Location: India
GMAT 1: 640 Q43 V34
GMAT 2: 630 Q47 V29
WE:Information Technology (Computer Software)
Send PM
Re: Set R contains five numbers that have an average value of 55 [#permalink]
PraPon wrote:
Sachin9 wrote:
Hi ,

Here's how I did..

smallest no: s
largest no: 3s+20

since mean = median,

thought that numbers are in AP.

so average= (last no+first no)/2


therefore 55=(s+3s+20)/2
=> s=22.5


now l=20+3s
=> l=87.25

range =l-s=65..
Please let me know where I am going wrong.


Sachin, you assumed that the numbers are in AP, but problem doesn't state that.
This set S = {29, 29, 55, 55, 107} has the maximum range i.e. 78 and mean/median 55.

Note that these numbers are not in AP/sequence. Hence you cannot take average of last & first to find the mean.



Thanks mate..
I thought that the numbers would be in AP since their median and mean were same.

I now understand that if the nos are in AP , then their median and mean will be same but the vice versa is not necessarily true.
User avatar
Manager
Manager
Joined: 15 Aug 2013
Posts: 180
Own Kudos [?]: 331 [0]
Given Kudos: 23
Send PM
Re: Largest possible range in Set R [#permalink]
Bunuel wrote:
Orange08 wrote:
Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?


78
77 1/5
66 1/7
55 1/7
52


{\(a_1\), \(a_2\), \(a_3\), \(a_4\), \(a_5\)}
As mean of 5 numbers is 55 then the sum of these numbers is \(5*55=275\);
The median of the set is equal to the mean --> \(mean=median=a_3=55\);
The largest number in the set is equal to 20 more than three times the smallest number --> \(a_5=3a_1+20\).

So our set is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(a_1+a_2+55+a_4+3a_1+20=275\).

The range of a set is the difference between the largest and smallest elements of a set.

\(Range=a_5-a_1=3a_1+20-a_1=2a_1+20\) --> so to maximize the range we should maximize the value of \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\).

Min possible value of \(a_2\) is \(a_1\) and min possible value of \(a_4\) is \(median=a_3=55\) --> set becomes: {\(a_1\), \(a_1\), \(55\), \(55\), \(3a_1+20\)} --> \(a_1+a_1+55+55+3a_1+20=275\) --> \(a_1=29\) --> \(Range=2a_1+20=78\)

Answer: A.


Hi Bunuel,

Since the statement says that the median = mean, aren't we supposed to assume that it's an evenly spaced set? If so, wouldn't a2 and a4 be different from a1 and a3?
Math Expert
Joined: 02 Sep 2009
Posts: 92902
Own Kudos [?]: 618791 [0]
Given Kudos: 81588
Send PM
Re: Largest possible range in Set R [#permalink]
Expert Reply
russ9 wrote:
Bunuel wrote:
Orange08 wrote:
Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?


78
77 1/5
66 1/7
55 1/7
52


{\(a_1\), \(a_2\), \(a_3\), \(a_4\), \(a_5\)}
As mean of 5 numbers is 55 then the sum of these numbers is \(5*55=275\);
The median of the set is equal to the mean --> \(mean=median=a_3=55\);
The largest number in the set is equal to 20 more than three times the smallest number --> \(a_5=3a_1+20\).

So our set is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(a_1+a_2+55+a_4+3a_1+20=275\).

The range of a set is the difference between the largest and smallest elements of a set.

\(Range=a_5-a_1=3a_1+20-a_1=2a_1+20\) --> so to maximize the range we should maximize the value of \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\).

Min possible value of \(a_2\) is \(a_1\) and min possible value of \(a_4\) is \(median=a_3=55\) --> set becomes: {\(a_1\), \(a_1\), \(55\), \(55\), \(3a_1+20\)} --> \(a_1+a_1+55+55+3a_1+20=275\) --> \(a_1=29\) --> \(Range=2a_1+20=78\)

Answer: A.


Hi Bunuel,

Since the statement says that the median = mean, aren't we supposed to assume that it's an evenly spaced set? If so, wouldn't a2 and a4 be different from a1 and a3?


For evenly spaced set mean = median, but the reverse is not necessarily true. Consider {1, 1, 2, 2, 4} --> mean = median = 2, but the set is not evenly spaced.
GMAT Club Bot
Re: Largest possible range in Set R [#permalink]
 1   2   
Moderators:
Math Expert
92902 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne