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Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]
750 -> Aged 8 - 12

Next year -> 750 + 750/3 = 750 + 250 = 1000

So %age = 1000/1500 = 10/15 = 662/3 %

Answer - E
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Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]
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MitDavidDv wrote:
At a contest with 1,500 participants, 1/2 of the people are aged 8 to 12. Next year, the number of people aged 8 to 12 will increase by 1/3. After this change, what percentage of the total 1,500 people will the 8- to 12-year-olds represent?

A. 33%
B. 40%
C. 50%
D. 55%
E. 66 2/3%


I just wanted to mention a couple of things here:

* this is a pure ratio question; the number 1,500 is completely irrelevant, and you can ignore it if you like. When we increase something by 1/3, we are multiplying it by 1 + 1/3 = 4/3, so the answer here must be (1/2)*(4/3) = 2/3 = 66 2/3 %.

* you can certainly take advantage of the answer choices to get the answer without any computation. The fraction of 8-12 year olds has clearly increased, so D and E are the only candidates. D would be the answer if the increase were 10%; it's more than 10% so the answer must be E.
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Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]
Shalom!
I am currently working on my GMAT preparation @ Belmont University.
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Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]
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Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]
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