Of all the attendees at a dinner party, 40% were women. If

Me for D ..

This is How :

As per the question, this is what is given :
_________________________________
________Alone_____With_____Total___
Men________________________60
Women ____________________ 40
Total _____________________ 100

Statement -1: 50% i.e 1/2 of the males arrived with a woman i.e 30 men with 30 women. Which implies 10 women were alone and 30 men were alone.

_________________________________
________Alone_____With_____Total___
Men _____ 30______ 30______ 60
Women -----10______30______ 40
Total --------40______60______ 100

Hence statement 1 is suffiecient to answer the Question.

Statement 2 : 1/4th of the alone were women. Let the alone be x. Hence alone women .25x.

_________________________________
________Alone_____With___________Total___
Men .75x ______ 60-0.75x ______ 60
Women .25x ______ 40-0.25x ______ 40
Total x__ ______ _______ ______ 100


At 1st glance it looks impossible to solve this. But here to go .

Since men and women together come in pairs hence no of men coming together will be equal ti women coming together.

hence : 60 - 0.75x = 40-0.25x
20 = 0.50x
x = 40
And we can find fill the remaining table..

Hence St2 is also suff..

Hence D .