Paper test question cordinate geometry involving inequality : Quant Question Archive [LOCKED]
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 20 Jan 2017, 13:22

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Paper test question cordinate geometry involving inequality

Author Message
Manager
Joined: 01 Dec 2007
Posts: 57
Followers: 0

Kudos [?]: 1 [0], given: 0

Paper test question cordinate geometry involving inequality [#permalink]

### Show Tags

10 Sep 2008, 07:55
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

SVP
Joined: 07 Nov 2007
Posts: 1820
Location: New York
Followers: 34

Kudos [?]: 863 [0], given: 5

Re: Paper test question cordinate geometry involving inequality [#permalink]

### Show Tags

10 Sep 2008, 08:09
blover wrote:

2x-3y <= -6
--> y>= 2/3x+6

draw the line y=2/3x+6 on XY plane.
this line cuts throw I,II,III co-ordinatesl.
y>2/3x+6 represents above the line.. which is also not in IV quadrant.

to lie in IV quadrant x should be postive and y shouldbe negative..

when x postive.. y is always +ve.

So Ans IV (E)
_________________

Smiling wins more friends than frowning

Current Student
Joined: 11 May 2008
Posts: 556
Followers: 8

Kudos [?]: 174 [0], given: 0

Re: Paper test question cordinate geometry involving inequality [#permalink]

### Show Tags

10 Sep 2008, 08:37
x2suresh wrote:
blover wrote:

2x-3y <= -6
--> y>= 2/3x+6

draw the line y=2/3x+6 on XY plane.
this line cuts throw I,II,III co-ordinatesl.
y>2/3x+6 represents above the line.. which is also not in IV quadrant.

to lie in IV quadrant x should be postive and y shouldbe negative..

when x postive.. y is always +ve.

So Ans IV (E)

good one suresh!!!
nice explanation
SVP
Joined: 29 Aug 2007
Posts: 2492
Followers: 67

Kudos [?]: 734 [0], given: 19

Re: Paper test question cordinate geometry involving inequality [#permalink]

### Show Tags

10 Sep 2008, 08:45
blover wrote:

alternatively - just plug in:

if you do that, values for (x, y) satisfies for all quadrants but IV.

for ex: if x = 1 and y = -1
2x - 3y = 2+3 = 5 which is greater than -6.

any +ve value for x and -ve value for y donot satisfy the inequality 2x - 3y =< - 6.
_________________

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

GT

Manager
Joined: 01 Dec 2007
Posts: 57
Followers: 0

Kudos [?]: 1 [0], given: 0

Re: Paper test question cordinate geometry involving inequality [#permalink]

### Show Tags

10 Sep 2008, 09:48
LESSON - The General Objective of this lesson is to study linear inequalities.

PERFORMANCE OBJECTIVES - At the end of this lesson the student will be able to graph linear inequalities in two variables.

Linear Inequalities in Two Variables - Linear inequalities can be graphed almost the same way we graph linear equations. Consider the example from the previous section. The graph of the equation

2x - 3y = 6

Every point on the line satisfies the equation

2x - 3y = 6

This means that if you choose any point in the region above or below the line, those points will satisfy one of the following inequalities.

2x - 3y > 6

or

2x - 3y < 6

All you need to do is choose a test point to decide which it is. The test point will usually be (0,0).

Example - Graph the inequality

2x - 3y > 6 .

Step 1 - Solve the related equality for y.

Step 2 - Determine two points by choosing suitable values for x. Let x = 0 and 3. Then y equals -2 and 0 respectively.
Step 3 - Locate these points A(0,-2), B(30) and draw a straight line through them, completely dividing the plane into two regions.
Step 4 - Choose the test point (0,0) and substitute it into the original inequality, to see if it satisfies the inequality.
If it does, the region the test point is in, is the solution.
If it doesn't, the region the test point is not in, is the solution.
2(0) - 3(0) = 0 > 6 No.

Therefore the solution is the region below the line -

2x - 3y = 6.
Re: Paper test question cordinate geometry involving inequality   [#permalink] 10 Sep 2008, 09:48
Display posts from previous: Sort by

# Paper test question cordinate geometry involving inequality

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.